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3 years ago

Minimo comun multiplo de 3 y 9 por favor

Mathematics

1 answer:

Mamont248 [21]3 years ago

7 0

9 is itself a multiple of 3, so the least common multiple of 3 and 9 is 9 itself

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Please help me answer this question

ratelena [41]

By the definition of the hyperbolic function tanh x, we have proven that $\frac{1-tanh \ x}{1 + tanh \ x}=e^{-2x}$

<h3>Hyperbolic functions & Proof of identities </h3>

By definition

$tanh \ x=\frac{e^{x} -e^{-x}}{e^{x} +e^{-x}}$

Then,

$\frac{1-tanh \ x}{1 + tanh \ x}=\frac{1-\frac{e^{x} -e^{-x}}{e^{x} +e^{-x}} }{1+ \frac{e^{x} -e^{-x}}{e^{x} +e^{-x}} }$

$=1-\frac{e^{x} -e^{-x}}{e^{x} +e^{-x}} \div (1+ \frac{e^{x} -e^{-x}}{e^{x} +e^{-x}} })$

$=\frac{e^{x} +e^{-x}-(e^{x} -e^{-x})}{e^{x} +e^{-x}} \div (\frac{e^{x} +e^{-x}+e^{x} -e^{-x}}{e^{x} +e^{-x}} })$

$=\frac{e^{x} +e^{-x}-e^{x} +e^{-x}}{e^{x} +e^{-x}} \div \frac{e^{x} +e^{-x}+e^{x} -e^{-x}}{e^{x} +e^{-x}} }$

$=\frac{e^{-x}+e^{-x}}{e^{x} +e^{-x}} \div \frac{e^{x} +e^{x} }{e^{x} +e^{-x}} }$

$=\frac{2e^{-x}}{e^{x} +e^{-x}} \div \frac{2e^{x} }{e^{x} +e^{-x}} }$

$=\frac{2e^{-x}}{e^{x} +e^{-x}} \times \frac{e^{x} +e^{-x}}{2e^{x}}$

$=\frac{2e^{-x}}{1} \times \frac{1}{2e^{x}}$

$=\frac{2e^{-x}}{2e^{x}}$

$=\frac{e^{-x}}{e^{x}}$
$=e^{-x} \times \frac{1}{e^{x}}$

$= e^{-x} \times e^{-x}$

$= e^{-x+-x}$

$= e^{-x-x}$

$= e^{-2x}$

Hence, we have proven that $\frac{1-tanh \ x}{1 + tanh \ x}=e^{-2x}$

Learn more on Proof of Identities here: brainly.com/question/2561079

#SPJ1

6 0

2 years ago

Help? 2+2-8+6-2+9+5-6+6-3+8-1+7-0+8-1+10-2+11+

SOVA2 [1]

Answer:

Step-by-step explanation:

2+2 = 4

4 - 8 = -4

-4 + 6 = 2

2 - 2 = 0

0 + 9 = 9

9 + 5 = 14

14 - 6 = 8

8 + 6 = 14

14 - 3 = 11

11 + 8 = 19

19 - 1 = 18

18 + 7 = 25

25 - 0 = 25

25 + 8 = 33

33 - 1 = 32

32 + 10 = 42

42 - 2 = 40

40 + 11 = 51

6 0

4 years ago

2x - y=5<br> x + 3y = 7<br> What is the value of the system determinant?<br> 5<br> 7<br> 6

Viktor [21]

Answer:

A=7

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

PLEASE help me with this question! This is really urgent! No nonsense answers please.

ipn [44]

Answer:

The second table of values.

Step-by-step explanation:

Let's put the x-values in the second table of values in correct number order:

x: -3, -2, -1, 0, 1

Now, let's write out the y-values in correct number order:

y: 1/4, 1, 4, 16, 64

Finally, let's rewrite the second table of values with the x-values in order and the corresponding y-values underneathe:

x: -3, -2, -1 0 1

y: 64, 16, 4, 1, 1/4

As it can be seen, as the x-values get bigger in value, the y-values get smaller exponentially, which is the definition of exponential decay.

6 0

3 years ago

14,800 at 6% compounded semiannually for 4 years.. I need to know the interest and the compound amount

Zepler [3.9K]

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{compounded amount}\\
P=
\begin{array}{llll}
\textit{original amount}\\
\textit{deposited}
\end{array}\to &\$14,800\\
r=rate\to 6\%\to \frac{6}{100}\to &0.06\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semi-annually, meaning twice}
\end{array}\to &2\\

t=years\to &4
\end{cases}$

now, that will give you "A", or the compounded amount

what's the interest earned? well, subtract the original amount, the Principal, from A, A - P, and you'd be left with the earned interest

--------------------------------------------------------------------------------------------
$\bf A=14,800\left(1+\frac{0.06}{2}\right)^{2\cdot 4}$

6 0

3 years ago