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2 years ago

In a classroom, for every 8 girls there are 5 boys. What is the ratio of boys to girls?

Mathematics

2 answers:

OleMash [197]2 years ago

4 0

Answer:

8 to 5

Step-by-step explanation:

MrRa [10]2 years ago

3 0

Answer:

5:8

Step-by-step explanation:

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Find the value of x.

iogann1982 [59]

Answer:

4.4

Step-by-step explanation:

x is hypotenuse of the right triangle.

One leg is 2.4 in.

Second leg = 7.4/2 = 3.7 in.

Using Pythagorean theorem

Hypotenuse²= (first leg)² + (second leg)²

x² = 2.4² + 3.7² = 19.45 in²

x=√19.45 ≈ 4.4 in

5 0

2 years ago

Which statements are true for the functions g(x)=x^2 and h(x)=-x^2? Check all that apply

galina1969 [7]

Answer:

if x=0 then they have same value

1 and 2 options are out

for x=-1

g(-1)=1

h(-1)=-1

3 is true

4th

FALSE

for all values except 0, g(x)>h(x)

correct ones are

g(x) > h(x) for x = -1.

For positive values of x, g(x) > h(x).

For negative values of x, g(x) > h(x).

Step-by-step explanation:

4 0

2 years ago

How exactly do you do this I understand this a little more but need a little push :(

Hitman42 [59]

Answer:

(2, 12)

Step-by-step explanation:

You do it by adding

2 and 0.

4 and 8.

3 0

2 years ago

Solving Rational Functions Hello I'm posting again because I really need help on this any help is appreciated!!

Greeley [361]

Answer:

x = √17 and x = -√17

Step-by-step explanation:

We have the equation:

$\frac{3}{x + 4} - \frac{1}{x + 3} = \frac{x + 9}{(x^2 + 7x + 12)}$

To solve this we need to remove the denominators.

Then we can first multiply both sides by (x + 4) to get:

$\frac{3*(x + 4)}{x + 4} - \frac{(x + 4)}{x + 3} = \frac{(x + 9)*(x + 4)}{(x^2 + 7x + 12)}$

$3 - \frac{(x + 4)}{x + 3} = \frac{(x + 9)*(x + 4)}{(x^2 + 7x + 12)}$

Now we can multiply both sides by (x + 3)

$3*(x + 3) - \frac{(x + 4)*(x+3)}{x + 3} = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}$

$3*(x + 3) - (x + 4) = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}$

$(2*x + 5) = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}$

Now we can multiply both sides by (x^2 + 7*x + 12)

$(2*x + 5)*(x^2 + 7x + 12) = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}*(x^2 + 7x + 12)$

$(2*x + 5)*(x^2 + 7x + 12) = (x + 9)*(x + 4)*(x+3)$

Now we need to solve this:

we will get

$2*x^3 + 19*x^2 + 59*x + 60 = (x^2 + 13*x + 3)*(x + 3)$

$2*x^3 + 19*x^2 + 59*x + 60 = x^3 + 16*x^2 + 42*x + 9$

Then we get:

$2*x^3 + 19*x^2 + 59*x + 60 - ( x^3 + 16*x^2 + 42*x + 9) = 0$

$x^3 + 3x^2 + 17*x + 51 = 0$

So now we only need to solve this.

We can see that the constant is 51.

Then one root will be a factor of 51.

The factors of -51 are:

-3 and -17

Let's try -3

p( -3) = (-3)^3 + 3*(-3)^2 + +17*(-3) + 51 = 0

Then x = -3 is one solution of the equation.

But if we look at the original equation, x = -3 will lead to a zero in one denominator, then this solution can be ignored.

This means that we can take a factor (x + 3) out, so we can rewrite our equation as:

$x^3 + 3x^2 + 17*x + 51 = (x + 3)*(x^2 + 17) = 0$

The other two solutions are when the other term is equal to zero.

Then the other two solutions are given by:

x = ±√17

And neither of these have problems in the denominators, so we can conclude that the solutions are:

x = √17 and x = -√17

6 0

2 years ago

BRAINLIEST FOR RIGHT ANSWER!!

julsineya [31]

Answer: ${\boxed{h(x+4)=\frac{9+3x}{8+x}}}$

Concept:

In a function f(x), it represents a function in terms of x or for x. Therefore, to find the values in the function, substitute values within the parenthesis to solve.

Solve:

Given information

$h(x)=\frac{-3+3x}{4+x}$

Need to find

$h(x+4)$

Substitute (x + 4) to the position of x

$h(x+4)=\frac{-3+3(x+4)}{4+(x+4)}$

Distributive property on the numerator

$h(x+4)=\frac{-3+3x+12}{4+(x+4)}$

Combine like terms

$h(x+4)=\frac{-3+12+3x}{4+4+x}$

$\boxed{h(x+4)=\frac{9+3x}{8+x}}$

Hope this helps!! :)

Please let me know if you have any questions

5 0

1 year ago