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2 years ago

How to graph polynomials F(x) = x 3 + ²+18

Mathematics

1 answer:

Black_prince [1.1K]2 years ago

4 0

Answer:

6x=1

Step-by-step explanation:

I don't really know how to do this so I just put something

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Sin(5x+20)

WINSTONCH [101]

Answer:

Yes.

Step-by-step explanation:

Just like normal algebra, you factor our the common factor, in this case, 5.

Thus,

$\sin(5(x + 4))$

4 0

3 years ago

WORTH ALOT!!! 25) A hockey player signs a contract with a starting salary of $840,000 per year and an annual increase of 6.5% be

Oduvanchick [21]

the answer is A I hope this helps

6 0

2 years ago

jane passes a signpost saying paris 8km how many miles is she from paris when she passes the signpost

-Dominant- [34]

Answer:

Step-by-step explanation:

3 0

2 years ago

6. If you draw 35 lines on a piece of paper so that no two lines are parallel to each

umka2103 [35]

The point of intersection is the point where lines intersect.

There will be 595 intersections for 35 lines, where no 3 lines are concurrent.

Given

$n = 35$ --- the number of lines

$d = 3$ --- no three lines are concurrent

When no three line are concurrent, it means that no three lines meet at the same point.

So, the sequence of intersection is:

0 intersection for 1 line
1 intersection for 2 lines
3 intersections for 3 lines
6 intersections for 4 lines

Following the above sequence, the number of intersections for n lines is:

$n_k = \frac{n \times (n - 1)}{2}$

In this case, $n = 35.$

So, we have:

$n_k = \frac{35 \times (35 - 1)}{2}$

$n_k = \frac{35 \times 34}{2}$

$n_k = 35 \times 17$

$n_k = 595$

Hence, there will be 595 intersections for 35 lines, where no 3 lines are concurrent.

Read more about lines of intersections at:

brainly.com/question/22368617

7 0

2 years ago

Read 2 more answers

Find the area of the triangle with the given base and height. b = 3 m and h = 10 1/2 m

svetoff [14.1K]

Statement:

The base of a triangle is 3m and its height is $10 \frac{1}{2}$ m.

To find out:

The area of the triangle.

Solution:

Given, base = 3m, height = $10 \frac{1}{2}$ m
We know,

$\sf \: area \: \: of \: \: a \: \: triangle = \frac{1}{2} \times base \: \times height$

Therefore, the area of the triangle

$\sf = (\frac{1}{2} \times 3 \times 10 \frac{1}{2} ) {m}^{2} \\ \sf = ( \frac{1}{2} \times 3 \times \frac{21}{2} ) {m}^{2} \\ = \sf \frac{63}{4} {m}^{2} \\ = \sf 15\frac{3}{4} {m}^{2}$

Answer:

The area of the triangle is $\sf \: 15 \frac{3}{4} {m}^{2}$

Hope you could understand.

If you have any query, feel free to ask.

5 0

2 years ago

Read 2 more answers