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suter [353]
3 years ago
8

The area of a rectangular wall of a barn is 252 square feet. Its length is 10 feet longer than twice its width. Find the length

and width of the wall of the barn.
Mathematics
1 answer:
valentinak56 [21]3 years ago
7 0

Answer: Length = 28 feet and width = 9 feet

Step-by-step explanation:

Let x = width of the wall.

Then, Length of the wall =  10+2x

Since , Area of rectangle = length x width

Then, as per given,

252= (10+2x)x\\\\\Rightarrow\ 252=10x+2x^2\\\\\Rightarrow\ 2x^2+10x-252=0\\\\\Rightarrow\ x^2+5x-126=0\\\\\Rightarrow\ x^2+14x-9x-126=0\\\\\Rightarrow\ (x+14)-9(x+14)=0\\\\\Rightarrow\ (x+14)(x-9)=0\\\\\Rightarrow\ x=-14 \ or \ x= 9

Since width cannot be negative , so x = 9

So width = 9 feet and length = 10+2(9)=10+18 = 28 feet

Hence, length is 28 feet and width is 9 feet of the wall of the barn.

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Is my answer correct? 10 points + brainleist!
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Answer:

your answer is incorrect.  The correct answer is  h=-13  and k=13 .

Step-by-step explanation:

If a quadratic function is f(x)=ax^2+bx+c and a>0, then minimum value of the function at point \left(-\dfrac{b}{2a},f(-\dfrac{b}{2a})\right).

The given function is

f(x)=x^2+bx+182

Here, a=1, b=b and c=182. So.

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Put x=-\dfrac{b}{2} in the given function to find the minimum value of the function.

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We know that minimum value is 13. So,

13=\dfrac{b^2}{4}-\dfrac{b^2}{2}+182

13-182=-\dfrac{b^2}{4}

-169=-\dfrac{b^2}{4}

169\times 4=b^2

Taking square root on both sides.

13\times 2=b

b=26

The value of b is 26.

So, the given function is  

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Now, add and subtract square of half of coefficient of x.

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f(x)=(x+13)^2+13

On comparing with f(x)=(x-h)^2+k, we get

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k=13

Therefore, your answer is incorrect.

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