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suter [353]
4 years ago
8

The area of a rectangular wall of a barn is 252 square feet. Its length is 10 feet longer than twice its width. Find the length

and width of the wall of the barn.
Mathematics
1 answer:
valentinak56 [21]4 years ago
7 0

Answer: Length = 28 feet and width = 9 feet

Step-by-step explanation:

Let x = width of the wall.

Then, Length of the wall =  10+2x

Since , Area of rectangle = length x width

Then, as per given,

252= (10+2x)x\\\\\Rightarrow\ 252=10x+2x^2\\\\\Rightarrow\ 2x^2+10x-252=0\\\\\Rightarrow\ x^2+5x-126=0\\\\\Rightarrow\ x^2+14x-9x-126=0\\\\\Rightarrow\ (x+14)-9(x+14)=0\\\\\Rightarrow\ (x+14)(x-9)=0\\\\\Rightarrow\ x=-14 \ or \ x= 9

Since width cannot be negative , so x = 9

So width = 9 feet and length = 10+2(9)=10+18 = 28 feet

Hence, length is 28 feet and width is 9 feet of the wall of the barn.

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Answer:

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Step-by-step explanation:

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8 0
3 years ago
the sides of a triangular birdcage are consecutive intergers if tge perimeter is 114 cm what is tge length of each side
alexandr402 [8]
Let:
x = first consecutive integer (or first side of △)
x + 1 = second consecutive integer (or second side of △)
x + 2 = third consecutive integer (or third side of △)

The formula for a perimeter of △ is simply the addition of three sides (or length). Since the given perimeter is 114 cm,
x + x+1 + x+2 = 114
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Nadusha1986 [10]

Answer:

76m

Step-by-step explanation:

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Step-by-step explanation:

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