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2 years ago

∠1 and ∠2 are complementary angles. m∠1 = 72° What is the measure of ∠2?

Mathematics

2 answers:

inessss [21]2 years ago

8 0

Answer:

m∠2 = 18°

Step-by-step explanation:

Complementary angles: two angles that sum to 90°

⇒ m∠1 + m∠2 = 90°

⇒ 72° + m∠2 = 90°

⇒ m∠2 = 90° - 72°

⇒ m∠2 = 18°

Sidana [21]2 years ago

3 0

The required value of is m∠2 = 18°.

Given that,

First complementary adjacent angel m∠1 = 72°

We have to find,

Second complementary adjacent angle m∠2.

According to the question,

In geometry, the two angles are said to be complementary angles if they add up to 90 degrees.

Such as, m∠1 + m∠2 = 90°.

Where, m∠1 = 72°

Putting the value of m∠1 = 72° in the equation,

72° + m∠2 = 90°

m∠2 = 90° - 72°

m∠2 = 18°

Hence, The required value of is m∠2 = 18°.

For more information about Complementary adjacent angles click the link given below.

brainly.com/question/24502946

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Answer:

<h2>28% probability that every student in the group is a girl.</h2>

Step-by-step explanation:

In this problem we have independent events, that is, the event "picking a girl" doesn't affect an "picking a boy", also, picking picking a girl doesn't affect the probability of the other subjects.

So, the probability when the first girl is being picked is:

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Because among the total 9 students, there are 7 girls.

Now, after picking one girl, there remains 6 girls and 8 students to be picked. So, the probability of the second girl would be:

$P_{2}=\frac{6 \ girls}{8 \ students}$

Then, the probability of the third girl:

$P_{3}=\frac{5 \ girls}{7 \ students}$

The fourth girl probability:

$P_{3}=\frac{4 \ girls}{6 \ students}$

Therefore, the probability of picking all 4 girls would be the product of each probability, because events are independent (we use product when they are independent):

$P=\frac{7 \ girls}{9 \ students} \times \frac{6 \ girls}{8 \ students} \times \frac{5 \ girls}{7 \ students} \times \frac{4 \ girls}{6 \ students}\\P=\frac{5}{18}=0.28 \ (or \ 28\%)$

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finlep [7]

Question:

The box plots below show student grades on the most recent exam compared to overall grades in the class: two box plots shown. The top one is labeled Class. Minimum at 70, Q1 at 74, median at 83, Q3 at 92, maximum at 100. The bottom box plot is labeled Exam. Minimum at 60, Q1 at 81, median at 87, Q3 at 91, maximum at 95. Which of the following best describes the information about the medians? (1 point) Group of answer choices

•The exam outlier at 60 makes the IQR narrower and the median higher.

•The class data is more evenly spread, which pulls its median down.

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•The class Q3 is higher than the exam Q3.

Step-by-step explanation:

In the question we have two box plots

a) Box plots for class is given as

Minimum at 70, Q1 at 74, median at 83, Q3 at 92,

b) Box plots for exam is given as Minimum at 60, Q1 at 81, median at 87, Q3 at 91, maximum at 95.

When we compare the median of the class which is 83 and the median of the exam plots 87, we can see that the median of the exam is higher than the median of the class, hence the option

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From the options given, the only correct option which best describes the information about the medians is

"•The class Q3 is higher than the exam Q3".

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