The ball will hit the ground at 2 seconds.
Step-by-step explanation:
Given that,
The path of the ball = h(x)=−2x2+1x+6
Here,
x is the time while h is the height of ball.
When the ball will hit the ground, the height will become zero. Therefore,
h(x)=−2x2+1x+6
0 =−2x2+1x+6
or
2x2 -1x - 6 = 0
This is a quadratic equation, hence by applying quadratic equation formula:
here,
a = 2
b = -1
c = -6
Putting these values in formula, we get
x = 2, -3/2
As the time cannot be negative. Therefore, the ball will hit the ground at 2 seconds.
It would be 29 or if you multiply it would be different
The probability of one arrives within the next 10 minutes
when he already been waiting for one jour for a taxi is,
P (X > 70 | X > 60) = P (X > 10) = 1 – P (X ≤ 10)
= 1 – {1 – e ^ -((1 / 10) 10)} = e ^ -1
= 0.3679
The probability of one arrives within the next 10 minutes
when he already been waiting for one hour for a taxi is 0.3679
Answer:
Step-by-step explanation:
In calculator the answer is 1703.66666667
Start by setting up a factor tree for each number.
Factor in anyway that you'd like.
At the end, circle all prime numbers.
Remember, prime numbers are numbers
with only 2 factors, 1 and the number itself.
Now write these factors in least to greatest
multiplying them separate rows.
Circle factors they have in common.
Since 3 pairs of two's match up, multiply by 2 three times to get 8.
So the GCF is 8.
