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lana [24]
3 years ago
10

A rectangular room has an area of 16m2.the length of the room is 8 m. work out

Mathematics
1 answer:
lana66690 [7]3 years ago
6 0

Answer:

width : 2m²

perimeter: 20m

Step-by-step explanation:

area = length x width

16m² = 8m x x\\

\frac{16}{8} = x

x = 2

width = 2m

perimeter = length + length + width + width

perimeter = 8 + 8 + 2+ 2

perimeter = 20m

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18.36 is the answer.
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What is 123.45 rounded to the nearest tenths place
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Answer:

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Step-by-step explanation:

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HELP PLEASE ITS DUD TMR
sdas [7]

Answer:

Step-by-step explanation:

Product means multiply

(10x^4y^2)(3xy3)

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3 years ago
Find the projection of u = <–6, –7> onto v = <1, 1> a. <-13/2,-13/2> b. <39,91/2> c. <-13/1764,-13/17
Alexandra [31]
<h2>Answer:</h2>

a. <-13/2,-13/2>

<h2>Step-by-step explanation:</h2>

The projection of a vector u onto another vector v is given by;

proj_vu = (\frac{u.v}{|v|^2})v               ----------------(i)

Where;

u.v is the dot product of vectors u and v

|v| is the magnitude of vector v

Given:

u = <-6, -7>

v = <1, 1>

These can be re-written in unit vector notation as;

u = -6i -7j

v = i + j

<em>Now;</em>

<em>Let's find the following</em>

(i) u . v

u . v = (-6i - 7j) . (i + j)

u . v = (-6i) (1i) + (-7j)(1j)          [Remember that, i.i = j.j = 1]

u . v = -6 -7 = -13

(ii) |v|

|v| = \sqrt{(1)^2 + (1)^2}

|v| = \sqrt{2}

<em>Substitute these values into equation (i) as follows;</em>

proj_vu = [\frac{-13}{(\sqrt{2}) ^2}][i + j]

proj_vu = \frac{-13}{2} [i + j]

This can be re-written as;

proj_vu = \frac{-13}{2}i + \frac{-13}{2}j

proj_vu =

5 0
3 years ago
If someone has 30 books to pack in each box and each box only hold 7 books how many books are left
ahrayia [7]

Answer:

you have two books left over

Step-by-step explanation:

if you divide 30 by 7 you will get 4.2

that hows you have four boxes

to check yourself you can times 7 by 4 which will give you 28 and that shows you have two that wont fit

5 0
3 years ago
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