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Oxana [17]
3 years ago
5

What is 27 decreased by 32%

Mathematics
1 answer:
11Alexandr11 [23.1K]3 years ago
8 0
18.36 is the answer.
27 divided by 100 is .27
100-32 is 68, so you need to find 68 percent of 27.
.27 id 1% of 27, so you can easily multiply it by 68 and get 18.36
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during one month the orangevale parks and recreation district spent $5720 for various activities. they spent $1430 on mommy and
AysviL [449]

To solve this problem, we must figure out what percent of the total spending was spent on mommy and baby exercise programs. To figure this out, we should divide how much was spent on the mommy and baby exercise by the total amount spent on the district activities.

$1430/$5720 = 0.25

This is a percentage, or a portion out of 100, which means we must multiply this decimal by 100 to find its equivalent percentage.

0.25 * 100 = 25

Therefore, your answer is 25% of the total spending was spent on mommy and baby exercise programs.

Hope this helps!

5 0
3 years ago
Expand 2(x-1) <br> Expand 3(2x+3)<br> Expand 7(x+5) <br> Expand 5(2x-y)
Agata [3.3K]
Those are the answers
2x-2
6x+9
7x+35
10x-5y
7 0
2 years ago
To win a trivia game, Nathan must score at least 105 points. Each correct answer is worth \large 3\frac{1}{3} points, and each i
myrzilka [38]

Answer:

Nathan earned 100 points. he lost the trivia game by 5 points.

Step-by-step explanation

3\frac{1}{3} * 33 = 110 points earned

\frac{1}{2} * 20 = 10 points lost

110-10 = 100

Nathan earned 100 points. he lost the trivia game by 5 points.

3 0
3 years ago
The formula for wind chill C (in degrees Fahrenheit) is given by C = 35.74 + 0.6215T - 35.75v^0.16 + 0.4275Tv^0.16 where v is th
Diano4ka-milaya [45]

Answer:

dC = 2.44

Relative error = 19%

Step-by-step explanation:

C = 35.74 + 0.6215*T - 35.75*v^(0.16) + 0.4275*T*v^(0.16)

Δv = 3 ; ΔT = 1 , v = 23, T = 8

Use differential Calculus

dC = Cv.dv + Ct.dt

Cv = dC/dv = -5.72*v^(-0.84) + 0.0684*T*v^(-0.84)\\Ct = dC/dT = 0.6215 + 0.4275*v^(0.16)\\dC = modulus (Cv.dv) + modulus (CT.dT)\\dC = (-5.72*v^(-0.84) + 0.0684*T*v^(-0.84))* 3 + (0.6215 + 0.4275*v^(0.16))*1\\dC = 2.44

Relative Error

dC / C @(T = 8, v=23)  * 100 = 19 %

8 0
2 years ago
Please help ٩(๑òωó๑)۶​
otez555 [7]

Answer:

Height of the cliff = 13.66 m

Step-by-step explanation:

Let the height of the cliff is 'x' m and distance between the base of the cliff and the boat is 'y' m.

From right triangle AOC,

tan 30° = \frac{\text{Opposite triangle}}{\text{Adjacent side}}

\frac{1}{\sqrt{3}}=\frac{x}{y}

y = x\sqrt{3} ------(1)

From right angle triangle BOC,

tan 45° = \frac{x}{y-10}

1=\frac{x}{y-10}

x = y - 10

y = x + 10 -------(2)

From equations (1) and (2),

x\sqrt{3}=x+10

x(\sqrt{3}-1)=10

x=\frac{10}{\sqrt{3}-1 }

x = 13.66 m

Therefore, height of the cliff is 13.66 m.

7 0
3 years ago
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