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Yuliya22 [10]
2 years ago
10

Help please

Mathematics
1 answer:
Mariana [72]2 years ago
5 0

Answer:

The slope is the cost per hour.

$5 per hour

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7=62-b what would you do to find the value for b
Zina [86]
7=62-b collect the like terms
7-62=-b
-55=-b divide both sides by negative
55=b
4 0
3 years ago
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Describe the steps to graph the equation "f(x) = 14x + 1" on the coordinate axes. Mention the labels on the axes and the interva
Svetllana [295]
It's a linear function, so you only need 2 points and then connect them together.

Easiest way: x = 0 ->y = 1 ->(0,1)

x = 1->y = 15 ->(1,15)


7 0
3 years ago
Right trapezoid WXYZ is shown. Right trapezoid W X Y Z is shown. Sides X Y and W Z are parallel. Angle W is 73 degrees and angle
Sladkaya [172]

Answer:

∠WXY = 107°

Step-by-step explanation:

In a trapezoid, adjacent angles are supplementary, meaning they add up to 180°. ∠W and ∠WXY are adjacent, so they are supplementary. 180° - 73° = 107°.

Another way to do this is to know that there are 360° in a trapezoid. This is a right trapezoid, so two of the angles are 90°. One angle is 73°. 90° + 90° + 73° = 253°. 360° - 253° = 107°.

I hope this helps :))

3 0
3 years ago
Initially a ship and a submarine are stationary at sea level, positioned 1.78km apart. The submarine then manoeuvres to position
poizon [28]
I’m assuming ‘dives further’ means to go directly down

the angle of elevation of the ship from the submarine is equal to the angle of depression of the submarine from the ship, if we assume the sea level is perpendicular to ‘directly down’.

let both of these angles to be = $ when the submarine is at A and ¥ when the submarine is at B (excuse the lack of easily accessible variables as keys)

then this become a simple trig problem:

A)

Let O be the position of of the ship, and C be the original position of the submarine.

therefore, not considering direction

|OC| = 1.78km = 1780m

|CA| = 45m

these are the adjacent and opposite sides of a right angled triangle.

But tan($) = opp/adj = |CA|/|OC| = 45/1780

therefore $ = arctan(45/1780) which is roughly 1.45 degrees,

B)

similarly, noting that |CB| = |CA| + |AB| = 45 + 62 = 107m


tan(¥) = 107/1780

¥ = arctan(107/1780) which is roughly 3.44 degrees






4 0
2 years ago
What is 7,539 increased by 3200?
Vikki [24]
7539 + 3200 =  10739
the answer is 10,739
3 0
2 years ago
Read 2 more answers
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