Answer:
y = x - 3
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = 
with (x₁, y₁ ) = (6, 3) and (x₂, y₂ ) = (4, 1)
m = 
= 
= 1 , then
y = x + c ← is the partial equation
To find c substitute either of the 2 points into the partial equation
Using (4, 1 )
1 = 4 + c ⇒ c = 1 - 4 = - 3
y = x - 3 ← equation of line
Answer: (0, -6) , (1 , -4) , ( 2 , -2)
Step-by-step explanation:
A=(-1,4)=(xa,ya)→xa=-1, ya=4
B=(-2,1)=(xb,yb)→xb=-2, yb=1
C=(2,1)=(xc,yc)→xc=2, yc=1
Perimeter <span>of ∆ABC: P=AB+BC+AC
AB=d A-B=sqrt [ (xb-xa)^2+(yb-ya)^2 ]
AB=sqrt [ (-2-(-1))^2+(1-4)^2]
AB=sqrt [ (-2+1)^2+(-3)^2]
AB=sqrt [ (-1)^2+9]
AB=sqrt [ 1+9]
AB=sqrt [10]
AB=3.162277660
</span>BC=d B-C=sqrt [ (xc-xb)^2+(yc-yb)^2 ]
BC=sqrt [ (2-(-2))^2+(1-1)^2]
BC=sqrt [ (2+2)^2+(0)^2]
BC=sqrt [ (4)^2+0]
BC=sqrt [ 16+0]
BC=sqrt [16]
BC=4
AC=d A-C=sqrt [ (xc-xa)^2+(yc-ya)^2 ]
AC=sqrt [ (2-(-1))^2+(1-4)^2]
AC=sqrt [ (2+1)^2+(-3)^2]
AC=sqrt [ (3)^2+9]
AC=sqrt [ 9+9]
AC=sqrt [9*2]
AC=sqrt [9] * sqrt [2]
AC=3 sqrt [2]
AC=3 (1.414213562)
AC=4.242640686
P=AB+BC+AC
P=3.162277660+4+4.242640686
P=11.40491834
To the nearest tenth:
P=11.4
Answer: <span>The perimeter of ∆ABC is 11.4 units</span>
To solve this, you need to use cross multiplication. The first fraction, is 3/4 and the second is 6/x, with x meaning how much the container can hold. Multiply 3x(x) and 4x6 equating to 3x=24. From here, use algebra to solve for x, by dividing both sides by three.
Your final answer will be B) 8 qts
This (*) will be for multiplication
1. 5 (3m + 1)
2. 2x * (5x + y - 8)
3. 48y * (2y - x)
Hope this helps
