Answer:
value of a = 6.93 m
hence , (b.)
Step-by-step explanation:
the given triangle is a right angled triangle, so
by using trigonometry.
=》
![\tan(a) = \tan(30) = \frac{1}{ \sqrt{3} }](https://tex.z-dn.net/?f=%20%5Ctan%28a%29%20%20%20%3D%20%5Ctan%2830%29%20%20%3D%20%20%5Cfrac%7B1%7D%7B%20%5Csqrt%7B3%7D%20%7D%20)
and we know,
=》
![\tan(a) = \frac{a}{b}](https://tex.z-dn.net/?f=%20%5Ctan%28a%29%20%20%3D%20%20%5Cfrac%7Ba%7D%7Bb%7D%20)
so, by above values of tan ( a ) we get,
=》
![\frac{a}{b} = \frac{1}{ \sqrt{3} }](https://tex.z-dn.net/?f=%20%5Cfrac%7Ba%7D%7Bb%7D%20%20%3D%20%20%5Cfrac%7B1%7D%7B%20%5Csqrt%7B3%7D%20%7D%20)
=》
![\frac{a}{12} = \frac{1}{ \sqrt{3} }](https://tex.z-dn.net/?f=%20%5Cfrac%7Ba%7D%7B12%7D%20%20%3D%20%20%5Cfrac%7B1%7D%7B%20%5Csqrt%7B3%7D%20%7D%20)
=》
![a = \frac{12}{ \sqrt{3} }](https://tex.z-dn.net/?f=a%20%3D%20%5Cfrac%7B12%7D%7B%20%5Csqrt%7B3%7D%20%7D%20)
=》
![a = 4 \sqrt{3}](https://tex.z-dn.net/?f=a%20%3D%204%20%5Csqrt%7B3%7D%20)
=
=》
![a = 6.93](https://tex.z-dn.net/?f=a%20%3D%206.93)
hence, a = 6.93 m
Answer:
2.
Step-by-step explanation:
1+1=2
The equation that we can create from this situation is:
i = (190 – 5 x) * (29 + x)
where i is the income and x is the increase in daily rate
Expanding the equation:
i = 5510 + 190x – 145x - 5x^2
i = -5x^2 + 45x + 5510
Taking the 1st derivative:
di/dx = -10x +45
Set to zero to get the maxima:
-10x + 45 = 0
x = 4.5
So the cars should be rented at:
29 + x = 33.5 dollars per day
The maximum income is:
i = (190 – 5*4.5) * (33.5)
i = 5,611.25 dollars
Answer:
107/33
Step-by-step explanation:
107/33 is the rational number equivalent to 3 point 24 with a bar over 24.
The answer is 1
Hope this helped :)