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4 years ago

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(x÷5) + (x÷3) = 8/15 Help please!

1 answer:

Tamiku [17]4 years ago

6 0

$x\div5=\dfrac{x}{5},\ x\div3=\dfrac{x}{3}\\\\(x\div5)+(x\div3)=\dfrac{8}{15}\\\\\dfrac{x}{5}+\dfrac{x}{3}=\dfrac{8}{15}\ \ \ \ \ |\cdot15\\\\15\cdot\dfrac{x}{5}+15\cdot\dfrac{x}{3}=15\cdot\dfrac{8}{15}\\\\3\cdot\dfrac{x}{1}+5\cdot\dfrac{x}{1}=1\cdot\dfrac{8}{1}\\\\3x+5x=8\\\\8x=8\ \ \ \ |:8\\\\\boxed{x=1}$

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A square garden plot measures 180 square feet. A second square garden plot measures 320 square feet. How many more feet of fence

REY [17]

The second garden plot will require 8√5 feet more fence than the first garden plot.

Further explanation:

In order to find the fence, we have to find the perimeter of both squares

So,

Area of Square 1: A1=180 square feet

Area of Square 2: A2=320 Square feet

Let x be the side of square 1:

Then,

$A_1=x^2\\180=x^2\\Taking\ square\ root\ on\ both\ sides\\\sqrt{180}=\sqrt{x^2}\\x=\sqrt{2*2*3*3*5}\\x=\sqrt{2^2*3^2*5}\\x=2*3\sqrt{5}\\x=6\sqrt{5}$

For second square:

Let y be the side of second square

$A_2=y^2\\320=y^2\\Taking\ square\ root\ on\ both\ sides\\\sqrt{320}=\sqrt{y^2}\\y=\sqrt{2*2*2*2*2*2*5}\\y=\sqrt{2^2*2^2*2^2*5}\\y=2*2*2\sqrt{5}\\y=8\sqrt{5}$

Perimeter of First Square:

$P_1=4x\\=4(6\sqrt{5})\\=24\sqrt{5}\ feet$

Perimeter of Second Square:

$P_2=4y\\=4(8\sqrt{5})\\=32\sqrt{5}\ feet$

The smaller perimeter will be subtracted from larger perimeter to find that how much more fence will be needed.

$P_2-P_1=32\sqrt{5}-24\sqrt{5}\\=(32-24)\sqrt{5}\\=8\sqrt{5}\ feet$

The second garden plot will require 8√5 feet more fence than the first garden plot.

Keywords: Radicals, Operations on Radicals

Learn more about radicals at:

#LearnwithBrainly

6 0

4 years ago

33 1/3% of 75<br><br>plz help

Paraphin [41]

The answer is 25

x 33 1/3% = 75

75 / 33 1/3

0.3333

(75)(0.333) = 25

24.9999999 rounds to 25

Hope this helps, have a BLESSED day! :-)

6 0

3 years ago

I need help i need to simplify 7(2y+1)+3y

Artist 52 [7]

Simplified form : 17y + 7

5 0

3 years ago

Read 2 more answers

What is the average rate of change for h(t) between t=0 and t=2

nordsb [41]

Part a: Option D 18 feet per second

Part b: increasing

Solution:

Height $h(t)=-16 t^{2}+50 t+3$

Part a: To find the average rate of change for h(t) between t = 0 and t = 2.

Substitute t = 0 in h(t).

$h(0)=-16 (0)^{2}+50 (0)+3$

h(0) = 3

Substitute t = 2 in h(t).

$h(2)=-16 (2)^{2}+50 (2)+3$

h(2) = 39

Average rate of change formula:

$$=\frac{h(b)-h(a)}{b-a}$

Here, a = 0 and b = 2.

$$=\frac{h(2)-h(0)}{2-0}$

$$=\frac{39-3}{2}$

$$=\frac{36}{2}$

= 18

Average rate of change = 18 feet per second

Option D is the correct answer.

Part b:

This means height of the ball is increasing for 0 < x < 2.

6 0

3 years ago

victor needs 300 feet of rope.The rope he wants to buy is sold by yards.He knows that there are 3 feet in 1 yard.How many yards

barxatty [35]

We need to convert 300 feet to yards.

We know,

3 feet = 1 yard

Hence,

300 feet * 1 yard/3 feet = 300/3 = 100 yards

He should buy 100 yards

5 0

2 years ago