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Crank
3 years ago
15

If the number of Conference participants decreases by 20% compared to last year, there would be 1760 participants this year. If

the number of Conference participants increases by 25%, how many more participants would be there this year versus last year?
Mathematics
2 answers:
Basile [38]3 years ago
7 0
2,640 this year
2,112 last year

the 1760 is 20% less than - so 120% of 1760 is the previous year:
1760 * 1.2 = 2112

2112 increased by 25% is a total of 125%: 
2112 *1.25 = 2640
Leya [2.2K]3 years ago
5 0
Step 1 - 1760 ÷ 0.8 = 2200 ⇒This represents the # of conference participants                       form last year (decreased by 20%)

Step 2 - 2200 × 1.25 = 2750 ⇒ This represents the # of conference participants from this year (increased by 25%)

Step 3 - 2750 - 2200 = 550 ⇒ This represents the difference between last year's and this year's # of conference participants

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3 years ago
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3 0
3 years ago
WORTH 100 POINTS!
zzz [600]

Answer:

7miles

equations shown in work image below

work shown on the paper with more explanations because text is hard to write equations (sorry I used km but it is miles for your problem.)

:) please give a heart for thanks

and brainliest crown :)

Step-by-step explanation:

For both d=r*t

Each bikes to others house and leave at the same time so for Tony,

11 = 30*t

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for Gerry,

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So Tony got to Gerry's house 11/150 hours quicker than Gerry got to Tony's house.

Now they turn around and head back toward each other. If they leave at the same exact time, the elapsed time for each until they met would be the same so t (for tony) = t (for gerry), but Tony got a head start.

We start the stopwatch when Gerry turns around 11/150 hours after Tony has turned around. If Gerry's time to where they meet from Tony's house t(gerry), then Tony's time from Gerry's house is t(gerry) + 11/150

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3 years ago
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Answer:

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Answer:

A) 40

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