Complete question:
A student throws a heavy ball downward off the top of a building with a speed of 18m/s. The ball reaches a speed of 41m/s just before striking the ground. Neglect drag, find the height of the building.
Answer:
The height of the building is 69.235 m
Step-by-step explanation:
Given;
initial velocity of the ball, u = 18 m/s
final velocity of the ball, v = 41 m/s
The height of the building is equal to distance traveled by the ball downward.
Apply the following kinematic equation;
v² = u² + 2gh
where;
g is acceleration due to gravity
h is height of the building
41² = 18² + 2(9.8)h
1681 = 324 + 19.6h
19.6h = 1681 - 324
19.6h = 1357
h = 1357 / 19.6
h = 69.235 m
Therefore, the height of the building is 69.235 m
Answer:
Step-by-step explanation:
Given
--- rate
Required
Determine which solution is correct or incorrect
The solutions are not given. So, I will provide a general explanation
The amount (n) is calculated as:
So, we have:
The above is the general equation to solve for the amount, given h hours
When h = 2.5, we have:
The median average refers to number in the middle of the set. But we need to write it in chronological order.
Now the set becomes 57, 60, 62, 65.
Now find the number in the middle. In this case, it both 60 and 62.
But we need one number.
So, we will take the average of both of them.
60 + 62 = 122
122 / 2 = 61
So, 61 is the median of the set.
EDIT:
Big thanks to mkersten for finding two errors in my answer!
6. d
7. a
8. f
9. b
10. c
11. (7x3)+(7x2)=
21+14=35
7x5=35
12. (6x3)+(6x3)=
18+18=36
6x6=36
13. (2x3)+(6x3)=
6+18=24
8x3=24
14. (9x5)+(9x3)=
45+27=72
9x8=72
Answer:
(7.13 × 10^-3) x 40 = 285.2 x 10^-3 = 2.9 x 10^-1
Step-by-step explanation:
I think this is the answer i hope if it right or not but aleast I try on it .
