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2 years ago

HELPPPPPPPPP MEEEEEEEE PLEASEEEEEE

Mathematics

2 answers:

timofeeve [1]2 years ago

7 0

The answer is 32 because of PEMDAS

Dmitrij [34]2 years ago

4 0

Step-by-step explanation:

Hope it helps please give me brainliest

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Multiple choice<br> thanks

Tema [17]

The answer is c i think

8 0

2 years ago

Read 2 more answers

a) Γ(n) =∫[infinity]0tn−1e−tdta)Show that Γ(n+ 1) =nΓ(n) using integration by parts.b) Show that Γ(n+ 1) =n! , wherenis a positi

Nataliya [291]

$\Gamma(n)=\displaystyle\int_0^\infty t^{n-1}e^{-t}\,\mathrm dt$

a. Integrate by parts by taking

$u=t^{n-1}\implies\mathrm du=(n-1)t^{n-2}\,\mathrm dt$

$\mathrm dv=e^{-t}\,\mathrm dt\implies v=-e^{-t}$

Then

$\displaystyle\Gamma(n)=-t^{n-1}e^{-t}\bigg|_0^\infty+(n-1)\int_0^\infty t^{n-2}e^{-t}\,\mathrm dt$

We have

$\displaystyle\lim_{t\to\infty}\frac{t^{n-1}}{e^t}=0$

and so

$\Gamma(n)=(n-1)\displaystyle\int_0^\infty t^{n-2}e^{-t}\,\mathrm dt=(n-1)\Gamma(n-1)$

or, replacing $n\to n+1$ , $\Gamma(n+1)=n\Gamma(n)$ .

b. From the above recursive relation, we find

$\Gamma(n+1)=n\Gamma(n)=n(n-1)\Gamma(n-1)=n(n-1)(n-2)\Gamma(n-2)=\cdots=n(n-1)(n-2)\cdots2\cdot1\Gamma(1)$

Now,

$\Gamma(1)=\displaystyle\int_0^\infty e^{-t}\,\mathrm dt=1$

and so we're left with $\Gamma(n+1)=n!$ .

c. Using the previous result, we find $\Gamma(5)=4!=24$ .

d. If the question is asking to find $\Gamma(12)$ , then you can just use the same approach as in (c).

But if you're supposed to find $\Gamma\left(\frac12\right)$ , we have

$\displaystyle\Gamma\left(\frac12\right)=\int_0^\infty t^{-1/2}e^{-t}\,\mathrm dt$

Substitute

$u=t^{1/2}\implies u^2=t\implies 2u\,\mathrm du=\mathrm dt$

Then

$\displaystyle\Gamma\left(\frac12\right)=\int_0^\infty\frac1ue^{-u^2}(2u\,\mathrm du)=2\int_0^\infty e^{-u^2}\,\mathrm du=\frac{2\sqrt\pi}2=\sqrt\pi$

7 0

2 years ago

There florist can order roses in bunches of one dozen and lilies in bunches of 8. Last month she ordered the same number of rose

Levart [38]

Roses come in 12s lillies come in 8s.
24 is The smallest number of bunches she could have ordered because it is the lcm of 12 and 8.
If she ordered no more than 100 roses than she must have ordered the highest multiple of 24 that is less than 100 which is: 96
bunches of roses:96/12=8
Bunches of roses 96/8=12

Hope this helps :)

6 0

2 years ago

Karthik goes to office at 9.30 am and returns back at 6:00 pm.His lunch timings are 12:00 noon to 12:45 p.m.Rewrite these timing

fiasKO [112]

Answer:

Karthik goes to office at 09.30 and returns back at 18:00. His lunch timings are 12:00 to 12:45

6 0

3 years ago

What is the average of 5,0,12,9

Mila [183]

6.5 because you add up all your numbers and then divide by the amount of numbers you added
5+0+12+9=26
26/4=6.5

6 0

2 years ago

Read 2 more answers