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3 years ago

Given: Line AE≅Line BD; Line CD≅Line CE Prove:Line AC≅Line BC

Mathematics

1 answer:

Anettt [7]3 years ago

8 0

I’m not sure but I think it is AC

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What is the sum of the first six terms of the geometric series?<br><br> 2 – 6 + 18 – 54 + ...

weeeeeb [17]

Answer:

-364

Step-by-step explanation:

Each number is being multiplied by -3

2 , -6 , 18 , -54 , 162 , -486

Add them all up

-364

4 0

4 years ago

Read 2 more answers

HELP PLEASE I WILL MARK YOU AS A BRAINLIEST THANK YOU VERY MUCH!!

dybincka [34]

The answer is A) 5b

Lets try an example:

Lets say we have 3 boxes in total of both board games. We can solve for b since b = 3 in the example.

= 5b

= 5(3)

= 15 dice in total

We can check our answer by adding the amount of dice per box.

2 + 3 = 5

Then multiplying by the number of boxes.

5 * 3 = 15 dice total

7 0

3 years ago

The function f is defined as follows for the domain given.

Blizzard [7]

Answer:

range ={-6,-2,4,8}

Step-by-step explanation:

The given function is

$f(x) = 2x + 2$

The domain is given as:

domain = {-4,-2, 1,3}

To find the range, we plug in the domain and solve for the corresponding range value.

When x=-4,

$f( - 4) =2 \times - 4 + 2 = - 8 + 2 = - 6$

When x=-2,

$f( - 2) =2 \times - 2+ 2 = - 4+ 2 = - 2$

When x=1,

$f( 1) =2 \times 1 + 2 = 2 + 2 = 4$

When x=3,

$f( 3) =2 \times 3 + 2 = 6 + 2 = 8$

Therefore the range is {-6,-2,4,8}

3 0

3 years ago

16 e-mails to 6 text messages - 10 e-mails to 4 text messages proportional or non proportional

Gnom [1K]

Proportional us the correct answer

5 0

3 years ago

A farmer wishes to enclose a rectangular pasture with 1200 ft of fence. He needs to divide this rectangle into two smaller recta

Minchanka [31]

Answer: $60,000 ft^2$

Step-by-step explanation:

Given

total of 1200 ft of fence is available

Suppose rectangular pasture has following dimension as shown in figure.

total perimeter

$P=4a+3b$

$1200=4a+3b$

$4a=1200-3b$

$a=300-\frac{3}{4}b$

Area of rectangle is

$A=2a\times b$

$A=2(300-\frac{3}{4}b)b$

$A=2[300 b-\frac{3}{4}b^2]$

For maximum area, differentiate A w.r.t b

$\frac{\mathrm{d} A}{\mathrm{d} b}=300-\frac{3}{2}b=0$

$300=\frac{3}{2}b$

$b=200 ft$

so $a=300-150=150\ ft$

so area is

$A=2\times 150\times 200$

$A=60,000 ft^2$

4 0

3 years ago