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Marrrta [24]
3 years ago
7

If f(x) = 2x + 1, and g(x) = x - 3, then f(g(x)) = [ ? ]x + [ ]

Mathematics
1 answer:
ad-work [718]3 years ago
6 0

Answer:

First box +2

Second box -5

Step-by-step explanation:

Just an Example,

If f(x) = 2x + 1  and we need f(2) we would replace the x in the function with the number 2 because 2 is the domain of the function , so f(2) would become,

f(2) = 2(2) + 1

f(2) = 4 + 1 = 5

Now the question is what is f(g(x)) in this case the domain of the function is g(x). In simpler words we replace x with the function g(x) so here goes,

f(x)=2x+1\\g(x)=x-3\\f(g(x))=2(x-3)+1\\f(g(x))=2x-6+1\\f(g(x))=2x-5

so,

f(g(x)) = 2x - 5

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(-∞ 2] ∪ [-4/3 ∞ )

Step-by-step explanation:

Given compound inequality,

-9x+5\leq 17\text{ or }13x+25\leq -1

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-x\leq \frac{12}{9}\text{ or }x\leq -\frac{26}{13}   ( Division property of inequality )

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iris [78.8K]

Answer:

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Step-by-step explanation:

<em>1. Let us first write down the problem at hand: </em>3y^2 + y - 14

<em>2. Now let us break this expression into groups:  </em>

3y^2 - 6y + 7y - 14  ⇒ ( 3y^2 - 6y )( 7y - 14 )

<em>3. Factor 3y from 3y^2 - 6y:</em>

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<em>5. Substitute Step #3, 4 ⇒ Step #2:</em>

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