Answer:
DNA in each of the two daughter cells would have half of the radioactivity as compared to the radioactivity of the DNA of parent bacterium
Explanation:
DNA replication is a semi-conservative process and each of the newly formed double helices contains one parental strand and one newly formed DNA strand. The parent bacterium had both of its DNA strands radio-labeled. Replication of the parent DNA would form two DNA double helices each of which would contain one radio-labeled parental strand and one non-labeled newly formed DNA strand. Therefore, DNA of each daughter cell would exhibit half the radioactivity as that of the parental DNA.
The answer to 15 is no because the jaws box skips pass the hagfish
Here the sensitivity is very low that is the reason why the condition happened. The error resulted are not highly specific. The reason for binding is because the unnecessary binding occurred.
Agglutination between saline and O antigen shows that there is a contamination which is acting as an agglutination.
The contamination can present as an antiserum or as an antigen or may be in chemical or physical agents and they are termed as the responsible factors for agglutination.
Answer:
Increase occurs in fresh water input.
Decrease occurs in the salinity of the bay.
Explanation:
The low rate of fresh water input and the presence of high amount of salts in water decreases the population of producers such as grasses in bay ecosystem. Due to this decrease, the population of the marine animals decreases due to the low availability of food for herbivorous organism that lives in the bay. The negative feedback mechanisms will be achieved if increase occurs in fresh water input and decrease occurs in the salinity of the bay.
