Answer:
the second answer
Step-by-step explanation:
I took the test
378% is the correct answer. Divide 280 by 100 to find 1 percent. Then multiply by 135 to find 135%
Answer:
see below
Step-by-step explanation:
mROP= 125°
mSOQ= mROP= 125°
mROQ=mPOS= 180°-125°= 55°
<u>Sum of measures of all arcs in the circle= 2π</u>
mRP= mQS=2π*125/360=25/36π
mQR=mPS=2π*55/360=11/36π
mPRQ= half circle= 2π/2= π
mRPQ= 2π-mQR= 2π- 11/36π= 61/36π
Answer:
The 99% confidence interval for the mean commute time of all commuters in Washington D.C. area is (22.35, 33.59).
Step-by-step explanation:
The (1 - <em>α</em>) % confidence interval for population mean (<em>μ</em>) is:
![CI=\bar x\pm z_{\alpha /2}\frac{\sigma}{\sqrt{n}}](https://tex.z-dn.net/?f=CI%3D%5Cbar%20x%5Cpm%20z_%7B%5Calpha%20%2F2%7D%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D)
Here the population standard deviation (σ) is not provided. So the confidence interval would be computed using the <em>t</em>-distribution.
The (1 - <em>α</em>) % confidence interval for population mean (<em>μ</em>) using the <em>t</em>-distribution is:
![CI=\bar x\pm t_{\alpha /2,(n-1)}\frac{s}{\sqrt{n}}](https://tex.z-dn.net/?f=CI%3D%5Cbar%20x%5Cpm%20t_%7B%5Calpha%20%2F2%2C%28n-1%29%7D%5Cfrac%7Bs%7D%7B%5Csqrt%7Bn%7D%7D)
Given:
![\bar x=27.97\\s=10.04\\n=25\\t_{\alpha /2, (n-1)}=t_{0.01/2, (25-1)}=t_{0.005, 24}=2.797](https://tex.z-dn.net/?f=%5Cbar%20x%3D27.97%5C%5Cs%3D10.04%5C%5Cn%3D25%5C%5Ct_%7B%5Calpha%20%2F2%2C%20%28n-1%29%7D%3Dt_%7B0.01%2F2%2C%20%2825-1%29%7D%3Dt_%7B0.005%2C%2024%7D%3D2.797)
*Use the <em>t</em>-table for the critical value.
Compute the 99% confidence interval as follows:
![CI=27.97\pm 2.797\times\frac{10.04}{\sqrt{25}}\\=27.97\pm5.616\\=(22.354, 33.586)\\\approx(22.35, 33.59)](https://tex.z-dn.net/?f=CI%3D27.97%5Cpm%202.797%5Ctimes%5Cfrac%7B10.04%7D%7B%5Csqrt%7B25%7D%7D%5C%5C%3D27.97%5Cpm5.616%5C%5C%3D%2822.354%2C%2033.586%29%5C%5C%5Capprox%2822.35%2C%2033.59%29)
Thus, the 99% confidence interval for the mean commute time of all commuters in Washington D.C. area is (22.35, 33.59).
Hey there! :D
So, we want to multiply that by 2. The table represents one year at Weatherford College.
8,965*2= 17,930
I heard the question mention 'reasonable'. It also said 'meet the cost'. So I would assume that 17,930 meets most of the cost. I think that's what it wanted to have. A couple thousand dollars may be reasonable, but will it meet the cost? Probably not.
I would say "A" is the best answer.
I hope this helps!
~kaikers