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Alecsey [184]
3 years ago
5

36. Factorize x-12x + 20​

Mathematics
2 answers:
Yuri [45]3 years ago
7 0
Hope this helps! feel free to clarify

m_a_m_a [10]3 years ago
6 0

Answer:

{ \tt{ {x} - 12x + 20}} \\{ \tt{ =-11x + 20 }}

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If you bought a stock last year for a price $21, and it has risen 11% since then, how much is the stock worth now, to the neares
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Answer:

$23.31

Step-by-step explanation:

$21 x 1.11 = $23.31

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2 years ago
A line passes through the point (4 , 2) and has a slope of 5/4
lidiya [134]
Y - 2 = 5/4 ( x - 4 )

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y = 5x/4 - 3
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3 years ago
How do you solve the problem 6-3x=-2x
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6-3x=2x

In order to solve these, you first want to get all the variables on one side. So, you add 3x to both sides.

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3 years ago
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(1 p 18. Demarcus drew a pair of complementary angles. He drew one angle that had a measure of 48º. What was the measure of the
Hoochie [10]

Answer: 42

Step-by-step explanation:

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4 0
3 years ago
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A Cepheid variable star is a star whose brightness alternately increases and decreases. For a certain star, the interval between
sattari [20]

Answer:

a)

B'(t) = \dfrac{0.9\pi}{4.4}\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)

b) 0.09

Step-by-step explanation:

We are given the following in the question:

B(t) = 4.2 +0.45\sin\bigg(\dfrac{2\pi t}{4.4}\bigg)

where B(t) gives the brightness of the star at time t, where t is measured in days.

a) rate of change of the brightness after t days.

B(t) = 4.2 +0.45\sin\bigg(\dfrac{2\pi t}{4.4}\bigg)\\\\B'(t) = 0.45\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)\times \dfrac{2\pi}{4.4}\\\\B'(t) = \dfrac{0.9\pi}{4.4}\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)

b) rate of increase after one day.

We put t = 1

B'(t) = \dfrac{0.9\pi}{4.4}\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)\\\\B'(1) = \dfrac{0.9\pi}{4.4}\bigg(\cos(\dfrac{2\pi (1)}{4.4}\bigg)\\\\B'(t) = 0.09145\\B'(t) \approx 0.09

The rate of increase after 1 day is 0.09

8 0
3 years ago
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