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Kobotan [32]
3 years ago
14

If m∠1= (7x –19)°, and m∠2 = (x + 5)°, find m∠2.

Mathematics
1 answer:
IgorLugansk [536]3 years ago
7 0

Given :

∠m1 = ( 7x - 19 )° .

∠m2 = ( x + 5 )° .

To Find :

The value of x .

Solution :

Since , relation between angle ∠m1 and ∠m2 is not given .

Let , us assume that sum of ∠m1 and ∠m2 is 180° .

So ,

(7x-19)+(x+5)=180^{\circ}\\\\8x-14=180\\\\8x=194\\\\x=24.25^{o}

Angle ∠m2 = (24.25  + 5 )° = 29.25° .

Therefore , ∠m2 = 29.25° .

Hence , this is the required solution .

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Answer:

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Step-by-step explanation:

we know that

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so

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5 0
3 years ago
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Salsk061 [2.6K]

Answer: x=\frac{1}{2}

Explanation:

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3 0
4 years ago
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If F(x) = 5x-7 and G(x) = -2x+9 , what is F(G(x))?
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The graph of y = |2 is shifted to the left by 6 units.<br> What is the equation of the new graph?
Tasya [4]

Answer:

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When you are shifting up or down, you put the amount you are shifting outside the absolute value sign.

When shifting left on a graph, you usually think of subtraction. However, when dealing with absolute value graphs, when you are shifting left, you use addition, as you can see in this problem.

The same goes for right. You use subtraction when shifting right, contrary to what you may think.

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3 0
4 years ago
PLEASE HELP !!!!!!!!!!!!!
Akimi4 [234]

9514 1404 393

Answer:

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Step-by-step explanation:

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The multiplicity of the root at x=4 is also an even number, because the x-axis is not crossed. However, the graph is significantly flatter at that point (than at x=-2), meaning the multiplicity is greater than 2. It is at least 4.

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4 0
3 years ago
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