Cierto banco emplea 59 personas en dos sucursales. De esta gente, 27 son universitarios graduados. Si una cuarta parte de las pe
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Answer:
n=1849
Step-by-step explanation:
Previous concepts
A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".
The margin of error is the range of values below and above the sample statistic in a confidence interval.
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The population proportion have the following distribution
Solution to the problem
In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by and
. And the critical value would be given by:
The margin of error for the proportion interval is given by this formula:
(a)
And on this case we have that and we are interested in order to find the value of n, if we solve n from equation (a) we got:
(b)
Assuming that the proportion is estimated . And replacing into equation (b) the values from part a we got:
And rounded up we have that n=1849
Answer:
D is true, E is true, F is true
Step-by-step explanation:
Hello,
n is an odd number it means that n = 2a+1 where a is integer
A
this is <u>not</u> an odd number
B
this is <u>not</u> an odd number
C
this is <u>not</u> an odd number
D
so this is an odd number
E
so this is an odd number
F
this is an odd number
hope this helps