I don’t know the answer but I need points sorry
Answer:
she needs to subtract 5-3 first
Step-by-step explanation:
Answer:
The probability that the second card is a face card if it’s known that the first card was a face card is 0.0497
Step-by-step explanation:
Total number of face cards = 12
Total cards = 52
Probability of getting face card on first draw=![\frac{12}{52}](https://tex.z-dn.net/?f=%5Cfrac%7B12%7D%7B52%7D)
Remaining no. of face cards = 11
Remaining number of total cards = 51
Probability of getting face card on second draw=![\frac{11}{51}](https://tex.z-dn.net/?f=%5Cfrac%7B11%7D%7B51%7D)
The probability that the second card is a face card if it’s known that the first card was a face card =![\frac{12}{52} \times \frac{11}{51}= \frac{12}{52} \times \frac{11}{51}=0.0497](https://tex.z-dn.net/?f=%5Cfrac%7B12%7D%7B52%7D%20%5Ctimes%20%5Cfrac%7B11%7D%7B51%7D%3D%20%5Cfrac%7B12%7D%7B52%7D%20%5Ctimes%20%5Cfrac%7B11%7D%7B51%7D%3D0.0497)
Hence The probability that the second card is a face card if it’s known that the first card was a face card is 0.0497
Answer:
y=2x-4
Step-by-step explanation:
y-y1=m(x-x1)
y-(-4)=2(x-0)
y+4=2x-0
y=2x-0-4
y=2x-4
Answer:
35.46
Step-by-step explanation:
27.36+(8.1)=35.46