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The length of side walk is 500 feet
<em><u>Solution:</u></em>
Given that, A rectangle park measures 300 ft by 400 ft
Length = 300 feet
Width = 400 feet
A sidewalk runs diagonally from one comer to the opposite corner
We have to find the length of side walk
Which means, we have to find the length of diagonal of rectangle
<em><u>The diagonal of rectangle is given by formula:</u></em>
Where,
d is the length of diagonal
w is the width and l is the length of rectangle
<em><u>Substituting the values in formula, we get</u></em>
Thus length of side walk is 500 feet
A polynomial is said to be in standard form if it is written in the order of degree from highest to lowest from left to right.
The degree of a term of a polynomial is the exponent of the variable or the sum of the exponents of the variables of that term of the polynomial.
Thus, given the expression
has a degree of 6, and
has a degree of 6.
Thus, the exponent of the variable or the sum of the exponents of the variables of the next term of the polynomial must be less than or equal to 6 for the polynomal to be said to be in standars form.
Therefore, the <span>terms that could be used as the last term of the given expression to create a polynomial written in standard form are
</span>
The degree of a term of a polynomial is the exponent of the variable or the sum of the exponents of the variables of that term of the polynomial.
Thus, given the expression
Thus, the exponent of the variable or the sum of the exponents of the variables of the next term of the polynomial must be less than or equal to 6 for the polynomal to be said to be in standars form.
Therefore, the <span>terms that could be used as the last term of the given expression to create a polynomial written in standard form are
Answer:
(a) boxes of cat food had been sold.
(b) boxes of cat food had been sold.
Step-by-step explanation:
From the question,
Polly stacked the tins from five boxes of cat food onto an empty shelf and there were 15 tins of cat food in each box. That is,
5 × 15 tins of cat food were stacked onto the empty shelf.
5 × 15 = 75
Hence, 75 tins of cat food were stacked onto the empty shelf.
Also, from the question,
At the end of the week there were 20 tins left on the shelf and the rest of the tins had been sold, that is
75 - 20 tins had been sold
75 - 20 = 55
Hence, 55 tins of cat food had been sold.
To determine the number of boxes of cat food that had been sold,
Since there are 15 tins of cat food per box, then
we will divide 55 tins of cat food that had been sold by 15 tins of cat food per box
55 ÷ 15 =
Hence, boxes of cat food had been sold
(a) As a mixed number
Hence, boxes of cat food had been sold.
(b) As an improper fraction
Hence, boxes of cat food had been sold.