Answer:
0.625 = 62.5% probability that part B works for one year, given that part A works for one year.
Step-by-step explanation:
We use the conditional probability formula to solve this question. It is

In which
P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
P(A) is the probability of A happening.
The probability that part A works for one year is 0.8 and the probability that part B works for one year is 0.6.
This means that 
The probability that at least one part works for one year is 0.9.
This means that: 
We also have that:

So


Calculate the probability that part B works for one year, given that part A works for one year.

0.625 = 62.5% probability that part B works for one year, given that part A works for one year.
3) Answer: 8:9 (Defense:Offense)
16 and 18 need to be simplified. They're both divisible by 2, getting 8:9, and can't be simplified any more or they won't be whole numbers.
4) Answer: 1:3 (Hit:Bat times)
5 and 15 are divisible by 3, making 1 and 3.
5) Answer: 1:65 (Hours:Miles)
3 and 195 is divisible by 3. (195 is divisible by 3 because 1+9+5=15, getting the sum of numbers will get a smaller number, and if that number, 15 in this case, is divisible by 3, then the larger number is divisible by 3. 195/3=65, so 1:65
6) Answer: 1:3 (Potatoes:Servings)
8 and 24 is divisible by 8, getting 1 and 3.
Answer:
t=−0.543624 lemme know if i was right
Step-by-step explanation:
Answer:
40%
Step-by-step explanation: