28 people going.....3 vans and 1 car....8 people per van
if there is 8 people per van, and there is 3 vans....8 * 3 = 24 people take the vans......leaving 28 - 24 = 4 people taking the car <==
Ok, here we go:
5 cars total.
1. Rachel - first car in line, yellow, SUV
2. blue car (Rachel is in front of the blue car), convertible, Anton
3. minivan - third car in line, Diego
4. white car, sedan, Ingrid
5. green car, immediately behind white car, Yuna, pickup
We know that Rachel is first, a blue car is second and the minivan is third. We know that 3, 4 cannot be a convertible since one is a minivan and the other is a sedan. We also know that a yellow car is in front of the convertible.
Based off of that we know that car 5 cannot be a convertible since 4 is white and not yellow. So 1 or 2 is the convertible and SUV. But we know that Rachel is in front of a blue car and the yellow car is in front of a convertible so that makes car #2 the blue convertible and car #1 the yellow SUV.
Fill in what you do know and start to eliminate the outliers. Hope that helps.
We have 1.5 hours 30 minutes = 120 minutes;
1 hour 15 minutes = 75 minutes;
1.25 minutes = 85 minutes;
75 < 85 < 120
The median is 85 minutes.
Finally, 1 hour 15 minutes is the median.
Answer:
x = 13 , y = 29
Step-by-step explanation:
If you have any questions about the way I solved it, don't hesitate to ask!
