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jolli1 [7]
3 years ago
7

What is the radius of a circle given by equation x^2 + y^2 - 2x + 8y - 47 = 0

Mathematics
2 answers:
Lera25 [3.4K]3 years ago
7 0
X^2 + y^2 - 2x + 8y - 47 = 0
x^2 + y^2 - 2x + 8y = 47
(x^2 - 2x) + (y^2 + 8y) = 47
(x^2 - 2(1)x) + (y^2 + 2(4)y) = 47
(x^2 - 2(1)x + 1^2) + (y^2 + 2(4)y + 4^2) = 47 + 1^2 + 4^2
(x - 1)^2 + (y + 4)^2 = 64 = 8^2
r=8
tresset_1 [31]3 years ago
3 0

Answer:8

Step-by-step explanation:

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