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2 years ago

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After exercising, Malik checked his heart rate it was beating at 90 beats per minute. After 20 minutes he rechecked his heart ra

te it was 55 beats per minute. What is the percent decrease in his heart rate?

1 answer:

miskamm [114]2 years ago

7 0

Answer:

39%

Step-by-step explanation:

Hope this helped!

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The coordinates of the vertices of the triangle are (–8, 8), (–8, –4), and . Consider QR the base of the triangle. The measure o

Mademuasel [1]

The coordinates of the vertices of the triangle are
(–8, 8), (–8, –4), and<span> (10, –4)</span>.

Consider QR the base of the triangle. The measure of the base is b = 18 units, and the measure of the height is h = <span>12</span> units.

The area of triangle PQR is<span>108</span> square units.

4 0

3 years ago

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Help please I need it please please help me in it

Snezhnost [94]

Answer:

115.08

Step-by-step explanation:

6 0

2 years ago

Help me please i'm confused again

11Alexandr11 [23.1K]

Answer: 6¹⁰

Step-by-step explanation:

$\displaystyle\\6^4*6^6=\\\\6^{4+6}=\\\\6^{10}$

6 0

1 year ago

Which expression is equivalent to (x Superscript 27 Baseline y) Superscript one-third?.

marin [14]

To solve the problem we must know the basic exponential properties.

<h3>What are the basic exponent properties?</h3>

${a^m} \cdot {a^n} = a^{(m+n)}$

$\dfrac{a^m}{a^n} = a^{(m-n)}$

$\sqrt[m]{a^n} = a^{\frac{n}{m}}$

$(a^m)^n = a^{m\times n}$

$(m\times n)^a = m^a\times n^a$

The expression can be written as $x^9\sqrt[3]{y}$ .

Given to us

$(x^{27}y)^\frac{1}{3}$

$(x^{27}y)^\frac{1}{3}$

Using the exponential property $(m\times n)^a = m^a\times n^a$ ,

$=(x^{27}y)^\frac{1}{3}\\\\=x^{\frac{27}{3}}\times y^\frac{1}{3}\\\\=x^9\times y^\frac{1}{3}$

Using the exponential property $\sqrt[m]{a^n} = a^{\frac{n}{m}}$ ,

$=x^9\times y^\frac{1}{3}\\\\=x^9\times \sqrt[3]{y}\\\\=x^9 \sqrt[3]{y}$

Hence, the expression can be written as $x^9\sqrt[3]{y}$ .

Learn more about Exponent properties:

brainly.com/question/1807508

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1 year ago

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I need help please help me thanks please

Vitek1552 [10]

so we have a table of values, with x,y coordinates, so let's use any two of those points to get the slope of the table and use the point-slope form to get its equation

$~\hspace{2.7em}\stackrel{\textit{let's use}}{\downarrow }\qquad \stackrel{\textit{and this}}{\downarrow }\\\begin{array}{|lr|r|r|r|r|}\cline{1-6}x&0&1&2&3&4\\y&-1&3&7&11&15\\\cline{1-6}\end{array}\\\\[-0.35em]\rule{34em}{0.25pt}\\\\(\stackrel{x_1}{1}~,~\stackrel{y_1}{3})\qquad(\stackrel{x_2}{4}~,~\stackrel{y_2}{15})$

$\stackrel{slope}{m}\implies\cfrac{\stackrel{rise}{\stackrel{y_2}{15}-\stackrel{y1}{3}}}{\underset{run}{\underset{x_2}{4}-\underset{x_1}{1}}}\implies \cfrac{12}{3}\implies 4\\\\\\% point-slope intercept\begin{array}{|c|ll}\cline{1-1}\textit{point-slope form}\\\cline{1-1}\\y-y_1=m(x-x_1)\\\\\cline{1-1}\end{array}\implies y-\stackrel{y_1}{3}=\stackrel{m}{4}(x-\stackrel{x_1}{1})\\\\\\y-3=4x-4\implies y = 4x-1\implies \blacktriangleright y = 4x+(-1)\blacktriangleleft$

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2 years ago