Answer:
For bbff we have only 6.3% probability
Step-by-step explanation:
If the parents are heterozygous for both traits, them they are represented by:
BbFf × BbFf
Parent 1: BbFf
Parent 2: BbFf
We have to find the percentage of occurence of bb × ff, which is a child that has blue eyes and no freckles, with no dominant factor.
By distributing the possibilities in a Punnett square, <em>vide</em> picture. We have the following possibilities:
Genotype Count Percent
bBfF 4 25
BBfF 2 12.5
bBFF 2 12.5
bBff 2 12.5
bbfF 2 12.5
BBFF 1 6.3
BBff 1 6.3
bbFF 1 6.3
bbff 1 6.3
For bbff we have only 6.3% probability
Answer:
What do we have to solve for this?
Answer:
h = 1/2
Step-by-step explanation:
Step 1: Write equation
2.4(5h + 10) - 3 = 27
Step 2: Distribute
12h + 24 - 3 = 27
Step 3: Combine like terms
12h + 21 = 27
Step 4: Subtract 21 on both sides
12h = 6
Step 5: Divide both sides by 12
h = 6/12
Step 6: Simplify
h = 1/2
The answer to this problem is line segment
The distance between the 2 locations = 7 units
Step-by-step explanation:
Step 1:
Given,
Location of Hot dogs = (6,4)
Location of Mustard = (6,-3)
We need to find the distance between the two locations
Step 2:
Since the x coordinates of both the location are the same , they lie in the same line.
The first location is 4 units above the x axis and the second location is 3 units below the x axis.
Hence the distance between the 2 locations 4-(-3) = 7 units
Step 3 :
Answer :
The distance between the 2 locations = 7 units
