3/4 I’m pretty sure hejjejwiwiwjwnnsn
Answer: The answer is.......
2.875
Answer:
The mean is also increased by the constant k.
Step-by-step explanation:
Suppose that we have the set of N elements
{x₁, x₂, x₃, ..., xₙ}
The mean of this set is:
M = (x₁ + x₂ + x₃ + ... + xₙ)/N
Now if we increase each element of our set by a constant K, then our new set is:
{ (x₁ + k), (x₂ + k), ..., (xₙ + k)}
The mean of this set is:
M' = ( (x₁ + k) + (x₂ + k) + ... + (xₙ + k))/N
M' = (x₁ + x₂ + ... + xₙ + N*k)/N
We can rewrite this as:
M' = (x₁ + x₂ + ... + xₙ)/N + (k*N)/N
and (x₁ + x₂ + ... + xₙ)/N was the original mean, then:
M' = M + (k*N)/N
M' = M + k
Then if we increase all the elements by a constant k, the mean is also increased by the same constant k.
Answer:
Step-by-step explanation:
11/5 is 2 1/5 reduced
Answer: 5/11
Tip:
You can solve for these repeating fractions by putting the repeating digits over 9's!
For example, 0.33 repeating:
33/99 = 1/3
And in the case of your problem:
0.454545...
45/99 = 5/11 (simplify!)
