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SVETLANKA909090 [29]
3 years ago
15

PLEASE HELP MEEE !!!!

Mathematics
1 answer:
labwork [276]3 years ago
4 0

Given:

The figure of a trapezium.

To find:

The measures of missing angle m\angle K, m\angle M.

Solution:

In the given figure JK\parallel ML.

If a transversal line intersect the two parallel lines, then the same sides interior angles are supplementary angles.

m\angle J+m\angle M=180^\circ         (Supplementary angles)

87^\circ+m\angle M=180^\circ

m\angle M=180^\circ-87^\circ

m\angle M=93^\circ

Similarly,

m\angle L+m\angle K=180^\circ         (Supplementary angles)

51^\circ+m\angle K=180^\circ

m\angle K=180^\circ-51^\circ

m\angle K=129^\circ

Therefore, m\angle M=93^\circ and m\angle K=129^\circ.

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Yanka [14]
In a triangle, the three interior angles always add to 180°

m∠B = 180 - 30 - 80 = 70°

<span>D: 70</span>
4 0
4 years ago
Will give brainliest at the right answer ​
ioda

Answer:

1.) 40.0 2.) 75.00 3.) 140.00 4.) 200.00 5.) 500.00 6.) 1300.00 7.) 70.0000

8.) 10.00 9.) 245.00 10.) 900.00

4 0
3 years ago
( NO LINKS ) If x=7, is this equation true? 7 + 9x &gt; 73 *<br><br> A. Yes<br> B. No
elixir [45]

Answer:

\huge\mathfrak\red{Answer} \\  \\ 7 + 9x > 73 \\  \\ x = 7 \:  \:  \:  \:  \:  \: given \\  \\ 7 + (9 \times 7) > 73 \\  \\ 7 + 63 > 73 \\  \\ 70 > 73 \\  \\ but \: 70 \: is \: not \: grater \:  \: than73 \\  \\ so \: this \: equation \: is \: not \: true \\  \\ \huge\mathfrak\purple{Answer = no} \\  \\ \small\mathfrak\red{hope \: it \: helps...}

7 0
3 years ago
BRAINLIEST FOR CORRECT ANSWER: What is the area of this figure?
ki77a [65]

Step-by-step explanation:

The answer should be 578mi²

5 0
2 years ago
Lee las situaciones y realiza lo siguiente con cada una:
Julli [10]

Answer:

Part 1) see the explanation

Part 2) see the explanation

Part 3) see the explanation

Part 4) see the explanation

Step-by-step explanation:

<u><em>The question in English is</em></u>

Read the situations and do the following with each one:

Write down the magnitudes involved

Write which magnitude is the independent variable and which is the dependent variable

It represents the function that describes the situation

SITUATIONS:

1) A machine prints 840 pages every 30 minutes.

2) An elevator takes 6 seconds to go up two floors.

3) A company rents a car at S/ 480 for 12 days.

4) 10 kilograms of papaya cost S/ 35

Part 1) we have

A machine prints 840 pages every 30 minutes

Let

x ----> the time in minutes (represent the variable independent or input value)

y ---> the number of pages that the machine print (represent the dependent variable or output value)

Remember that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form k=\frac{y}{x} or y=kx

In this problem

we have a a proportional variation

so

The value of the constant of proportionality is equal to

 k=\frac{y}{x}

we have

y=840\ pages\\x=30\ minutes

substitute

 k=\frac{840}{30}=28\ pages/minute

The linear equation is

y=28x

Part 2) we have

An elevator takes 6 seconds to go up two floors.

Let

x ----> the time in seconds (represent the variable independent or input value)

y ---> the number of floors (represent the dependent variable or output value)

Remember that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form k=\frac{y}{x} or y=kx

In this problem

we have a a proportional variation

so

The value of the constant of proportionality is equal to

 k=\frac{y}{x}

we have

y=2\ floors\\x=6\ seconds

substitute

 k=\frac{2}{6}=\frac{1}{3}\ floors/second

The linear equation is

y=\frac{1}{3}x

Part 3) we have

A company rents a car at S/ 480 for 12 days.

Let

x ----> the number of days (represent the variable independent or input value)

y ---> the cost of rent a car (represent the dependent variable or output value)

Remember that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form k=\frac{y}{x} or y=kx

In this problem

we have a a proportional variation

so

The value of the constant of proportionality is equal to

 k=\frac{y}{x}

we have

y=\$480\\x=12\ days

substitute

 k=\frac{480}{12}=\$40\ per\ day

The linear equation is

y=40x

Part 4) we have

10 kilograms of papaya cost S/ 35

Let

x ----> the kilograms of papaya (represent the variable independent or input value)

y ---> the cost  (represent the dependent variable or output value)

Remember that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form k=\frac{y}{x} or y=kx

In this problem

we have a a proportional variation

so

The value of the constant of proportionality is equal to

 k=\frac{y}{x}

we have

y=\$35\\x=10\ kg

substitute

 k=\frac{35}{10}=\$3.5\ per\ kg

The linear equation is

y=3.5x

6 0
3 years ago
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