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Ulleksa [173]
2 years ago
6

What percent of the first 10 natural numbers are prime numbers? Answer in a percent please. :)

Mathematics
1 answer:
saul85 [17]2 years ago
6 0

So the first 10 are 1, 2, 3, 4, 5, 6, 7, 8, 9, 10. Since a prime number is only divisible by 1 and itself and greater than 1, our answers are 2, 3, 5, and 7. That's 4 numbers, or 4/10=0.4 of the 10. Since percentage is based out of 1, we can multiply 0.4 by 100 to get 40%. I hope that Helped :)


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g A trial jury of 6 people is selected from 20 people: 8 women and 12 men. What is the probability that the jury will have an od
cricket20 [7]

Answer: P(odd) = 0.499

Step-by-step explanation:

Given:

Total number of people = 20

Number of men = 12

Number of women = 8

Number of jury to be selected = 6

For the jury to have an odd number of women. it must have either of the three.

1. 1 woman , 5 men

2. 3 women, 3 men

3. 5 women, 1 man

The total possible ways of selecting the 6 people jury is;

N = 20C6 = 20!/6!(20-6)!

N = 38760

The possible ways of selecting;

Case 1 : 1 woman, 5 men

N1 = 8C1 × 12C5

N1 = 8 × 792 = 6336

Case 2 : 3 women , 3 men

N2 = 8C3 × 12C3

N2 = 12320

Case 3 : 5 women, 1 man

N3 = 8C5 × 12C1

N3 = 672

P(Odd) = (N1+N2+N3)/N

P(odd) = (6336+12320+672)/38760

P(odd) = 19328/38760

P(odd) = 0.499

6 0
2 years ago
IMAGE BELOW I WILL GIVE BRAINLIEST
diamong [38]

Answer:

for L 2, 2 and for LM it is -8,8

Step-by-step explanation:

easy

7 0
2 years ago
The table shows a gym class's average results for boys and
Rufina [12.5K]

Susan can jump at most 104 in during the long jump

<h3>Inequality</h3>

Inequality is an expression that show the non equal comparison of two or more variables and numbers.

From the table, the average result for females = 8ft 4in  = (8 * 12)in + 4in = 100 in

Since Susan could jump no farther than 4 inches more than the average distance for females, hence:

j ≤ 4 + 100

j ≤ 104 in

Susan can jump at most 104 in during the long jump

Find out more o Inequality at: brainly.com/question/24372553

5 0
2 years ago
At a college, 69% of the courses have final exams and 42% of courses require research papers. Suppose that 29% of courses have a
laila [671]

Answer:

a) 0.82

b) 0.18

Step-by-step explanation:

We are given that

P(F)=0.69

P(R)=0.42

P(F and R)=0.29.

a)

P(course has a final exam or a research paper)=P(F or R)=?

P(F or R)=P(F)+P(R)- P(F and R)

P(F or R)=0.69+0.42-0.29

P(F or R)=1.11-0.29

P(F or R)=0.82.

Thus, the the probability that a course has a final exam or a research paper is 0.82.

b)

P( NEITHER of two requirements)=P(F' and R')=?

According to De Morgan's law

P(A' and B')=[P(A or B)]'

P(A' and B')=1-P(A or B)

P(A' and B')=1-0.82

P(A' and B')=0.18

Thus, the probability that a course has NEITHER of these two requirements is 0.18.

3 0
2 years ago
What is 600000 minus 145782
svp [43]
454,218 Is The Answer
4 0
3 years ago
Read 2 more answers
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