the length of a pool 2 km long is represented on a map with a length of 20cm. what is the map scale used?
2 answers:
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Answer:
A. About 4,900 ft
Step-by-step explanation:
We want h such that ...
5 = 10·ln(h) -80
8.5 = ln(h) . . . . . . . add 80, divide by 10
e^8.5 = h ≈ 4914.8 . . . . take the antilog
h ≈ 4900 . . . . feet
