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Serga [27]
3 years ago
14

Which of the following equations, in its simplest form,

Mathematics
1 answer:
Ilya [14]3 years ago
3 0

Hi there!  

»»————- ★ ————-««

I believe your answer is:  

\boxed{x-1+x-2+x}

»»————- ★ ————-««  

Here’s why:  

⸻⸻⸻⸻ \boxed{\text{Simplifying the Expression...}}\\\\3x+2+(-5)\\----------------\\\rightarrow 3x+2-5\\\\\rightarrow\boxed{3x-3}\\\\\text{This is not an answer choice, so we would find an expression equivalent to the one above.}⸻⸻⸻⸻

\boxed{2 +3x+5}\\\\\rightarrow 3x + 5 + 2\\\\\rightarrow \boxed{3x + 7}\\\\\text{This is \textbf{NOT} equivalent.}

⸻⸻⸻⸻

\boxed{x-1+x-2+x}}\\\\\rightarrow x+x+x -1-2\\\\\rightarrow \boxed{3x-3}\\\\\text{This is \textbf{equivalent}.}\\\\\text{This answer choice and the expression given has the same result when simplified.}

⸻⸻⸻⸻

\boxed{-3-3x-1+x}}\\\\\rightarrow-3-1-3x+x\\\\\rightarrow -4-2x\\\\\rightarrow \boxed{-2x-4}\\\\\text{This is \textbf{NOT} equivalent.}

⸻⸻⸻⸻

\boxed{3-3x}\\\\\rightarrow{-3x+3}\\\\\text{This is \textbf{NOT} equivalent.}

⸻⸻⸻⸻

\text{Option B, } x-1 +x-2 + x, \text{ should be the correct answer.}

»»————- ★ ————-««  

Hope this helps you. I apologize if it’s incorrect.  

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5 0
3 years ago
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3 years ago
On Tuesday Conrad had 3 times as many sales as on Monday. On Wednesday, he had 9 times as many sales as on Monday. Over the thre
Vlad1618 [11]

Answer:

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Step-by-step explanation:

Let x be the no. of sales on Monday

We are given that On Tuesday Conrad had 3 times as many sales as on Monday.

So, Conrad had sales on Tuesday = 3x

We are also given that On Wednesday, he had 9 times as many sales as on Monday.

So, Conrad had sales on Wednesday = 9x

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7 0
2 years ago
You have 42,784 grams of a radioactive kind of curium. If its half-life is 18 years, how much will be left after 72 years?
s344n2d4d5 [400]

Answer:

2,674.14 g

Step-by-step explanation:

Recall that the formula for radioactive decay is

N = N₀ e^(-λt)

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t = time elapsed (given as 72 years)

e = exponential constant ( approx 2.7183)

If we substitute these into our equation:

N = N₀ e^(-λt)

= (42,787) (2.7183)^[(-0.0385)(72)]

= (42,787) (2.7183)^(-2.7726)

=  (42,787) (0.0625)

= 2,674.14 g

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The answer is 2 4/9.

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