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iren2701 [21]
3 years ago
6

A square playground has an area of 900 ft.what is the length of each side of the playground

Mathematics
2 answers:
Yanka [14]3 years ago
8 0

Answer:

Area \ of \ square =  l * l = l^2\\900 = l^2\\\sqrt{900} = l\\l = 30ft

Since sides are equal both sides are 30ft each

Bezzdna [24]3 years ago
6 0

Answer:

the answer is 225 square feet

Step-by-step explanation:

900÷4=225

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S=a1/1-r
valentinak56 [21]

Answer:

4

Step-by-step explanation:

This is an <em>infinite geometric series</em>. This has a sum of  \frac{a}{1-r}

Where

a is the first term, and

r is the common ratio (one term divided by the previous term)

Let's figure out the first 2 terms by plugging in n = 1 first and then n = 2 for the series.

<u />

<u>First term:</u>

3(\frac{1}{4})^{n-1}\\=3(\frac{1}{4})^{1-1}\\=3(\frac{1}{4})^0\\=3(1)\\=3

<u>Second term:</u>

3(\frac{1}{4})^{n-1}\\=3(\frac{1}{4})^{2-1}\\=3(\frac{1}{4})^1\\=3(\frac{1}{4})\\=\frac{3}{4}

<em>Let's see the common ratio:  \frac{\frac{3}{4}}{3}\\=\frac{3}{4}*\frac{1}{3}\\=\frac{1}{4}</em>

<em />

<em>Thus we have a = 3 and r = 1/4</em><em>. Plugging into the formula of the infinite sum, we get:</em>

<em>s=\frac{a}{1-4}=\frac{3}{1-\frac{1}{4}}=\frac{3}{\frac{3}{4}}=3*\frac{4}{3}=4</em>

<em />

<em>So, </em><em>the answer is 4</em>

4 0
3 years ago
Given: AB || DE , AD bisects BE.<br> Prove: ABC = DEC using the ASA postulate.
Ket [755]

Answer:

As per ASA postulate, the two triangles are congruent.

Step-by-step explanation:

We are given two triangles:

\triangle ABC and \triangle DEC.

AD bisects BE.

AB || DE.

Let us have a look at two properties.

1. When two lines are parallel and a line intersects both of them, then <em>alternate angles </em>are equal.

i.e. AB || ED and \angle B and \angle E are alternate angles \Rightarrow \angle B = \angle E.

2. When two lines are cutting each other, angles formed at the crossing of two, are known as <em>Vertically opposite angles </em>and they are are <em>equal</em>.

\Rightarrow \angle ACB = \angle DCE

Also, it is given that <em>AD bisects BE</em>.

i.e. EC = CB

1. \angle B = \angle E

2. EC = CB

3. \angle ACB = \angle DCE

So, we can in see that in \triangle ABC and \triangle DEC, two angles are equal and side between them is also equal to each other.

Hence, proved that \triangle ABC \cong \triangle DEC.

8 0
3 years ago
Olga flips 2 fair coins. What is the probability of obtaining a different result on each coin?
erica [24]

Answer:

2/4

Step-by-step explanation:

3 0
3 years ago
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What is 22% reduced as a fraction ??
Svet_ta [14]

Answer:

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Step-by-step explanation:

22% is 22/100

So, divide 22/100 by 2 to get 11/50, which cannot be simplified any further.

3 0
3 years ago
How to simplify : <br><br> √(1+√(1-x^2 )) - √(1-√(1-x^2 ))
muminat
√(1 + √(1 - x²)) - √(1 - √(1 - x²))
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1.414 - 0 - x^1/2 + x^1/2
1.414
4 0
4 years ago
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