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Aneli [31]
3 years ago
15

What are the solutions to the equation x2-12x + 20 = –20?

Mathematics
2 answers:
ladessa [460]3 years ago
5 0

x = 2, 10

Solve value of x by factoring, getting

(x - 2)(x - 10) = 0

kondaur [170]3 years ago
3 0
Standard: x=4
implicit: x-4=0
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2a +5 - 3a -12 please
chubhunter [2.5K]

Answer:

-7-a

Step-by-step explanation:

2a-3a +5-12

-a - 7

or -7-a

7 0
3 years ago
Read 2 more answers
Identify all factors of the expression 12x^2-14x-6
Evgen [1.6K]

Let's solve this by using the quadratic formula:

\frac{-b+-\sqrt{b^2-4ac} }{2a}


Note that we only use the coefficients so a=12, b=-14, and c=-6.

Plug values in the quadratic equation:

\frac{ -  ( - 14)± \sqrt{ {( - 14)}^{2} - 4(12)( - 6) } }{2(12)}

And so by evaluating those values we obtain:

\frac{14+-\sqrt{484} }{24}=\frac{14+-22}{24}  \\\\

Now we have two answers which are our factors one where we add another where we subtract and so:

First factor:

\frac{14+22}{24}=\frac{36}{24}=\frac{3}{2}


Second Factor:

\frac{14-22}{24}=\frac{-8}{24}=-\frac{1}{3}


And so your factors are

\frac{3}{2},-\frac{1}{3}

meaning that those are your roots/x-intercepts.


6 0
3 years ago
If a number is chosen at random from the set {1, 2, 3, 4, . . ., 18}, what is the probability that the number chosen is a factor
choli [55]
Looking at the set, we are given 18 elements. 17 is prime; it has only two factors: 1 and 17, since 1•17=17. So, the question is really asking what is the probability the numbers 1 or 17 is chosen. As mentioned earlier, 17 is prime, so there are two possible choices: 1 and 17.

P (probability) = possible outcomes / total outcomes

It is important to note that these events are “or” events, meaning that the probability can only be determined by choosing a 1 or a 17; you can’t randomly chose a 1 and 17 at the same time. So, the formula is:

P(A or B) = P(A) + P(B)

All this is saying is that given two possible outcomes, the probability occurs independent of each event; they don’t occur at the same time.

P(1 or 17) = P(1)/18 + P(1)/18

P(1 or 17) = 2/18

Since 17 is prime, it’s two and only factors are 1 and 17. The probability of randomly choosing a 1 or 17 is 2/18, meaning that there are 2 elements in the set out of a possible 18 elements that can be randomly chosen.

2/18 simplifies to 1/9


So, your answer is 1/9
5 0
2 years ago
Whts the factored answer
ratelena [41]

Answer:

(x-5)(x+5)

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
What is the resulting ordered pair if the value of the independent variable is 2?
Alla [95]
2, –6 is the correct answer
7 0
3 years ago
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