Let
be the number of students who eat cauliflower.
Therefore,
.
Let
be the total number of students surveyed.
Therefore, 
Thus, 

Now, for 90% confidence level, from the table we know that
.
The formula for the interval range of proportion of students is :

Plugging in the values we get:

Thus, Jane is 90% confident that the population proportion p, for students who eat cauliflower in her campus is between 5.398% and 15.114% (after converting the answer we got to percentage).
31/2 ÷ 7
= 31/2 ÷ 7/1
= 31/2 × 1/7
= 31/14
= 2/3/14
i am a mathematics teacher. if anything to ask please pm me
Answer:
A
Step-by-step explanation:
KAJAISJAKAHWJ 56791827282292881811827 mIllOn