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vladimir1956 [14]
3 years ago
6

Write an equation for the line that passes through the given points (-2,9) And (1 ,-3)​

Mathematics
1 answer:
babymother [125]3 years ago
5 0

Answer:

Finding slope: y2-y1/x2-x1

3-9/1+2

=-6/2

Divide 2 from both

=-3/1 or -3

Slope= -3

Finding y-intercept= y=mx+b

Choose any point on the line to plug in the x and the y then plug in the slope.

I choose (1,3)

3=-3×1+b

3=-3+b

Add 3 to both sides

6=b

Y-intercept=6

Equation: y=-3x+6

Step-by-step explanation:

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Help me please and no links
Burka [1]

Answer:

x = -2    

x=-12

Step-by-step explanation:

5 | x+7| +14 = 39

Subtract 14 from each side

5 | x+7| +14-14 = 39-14

5 | x+7|  = 25

Divide each side by 5

5 | x+7| /5 = 25/5

| x+7|  = 5

Make two equations, one positive and one negative

x+7 =5     x+7 = -5

Subtract 7 from each side

x+7-7 = 5-7    x+7-7 = -5-7

x = -2               x=-12

7 0
3 years ago
Read 2 more answers
Kara is using a collection of old buttons for a craft project.She sorts the buttons by their sizes.The line plot shows the resul
MariettaO [177]
.25*3=.75
.375*2=.75
.5*2=2.0
.625*2=1.25
.75*3=2.25
.875*2=1.75
1*2=2
1.25*2=2.5
1.5*2=3
1.5+2=3.5
1.25+2.25=3.5+3.5=7
3.5+1.75=5.25
5.25+4.5=9.75
9.75+3=12.75

answer = 12.75in^2
7 0
3 years ago
Read 2 more answers
The graph depicts the growth and costs using of line segment use the midpoint formula to approximate the cost during the year 19
marysya [2.9K]

Answer:

The approximate cost during the year 1987 was $7,533

Step-by-step explanation:

The complete question in the attached figure

we have

y -----> is the cost in dollars

x -----> is the year

Looking at the graph we have the points

(1983,5,047) and (1991, 10,019)

To determine the cost in the year 1987, find out the midpoint between the two given points

The formula to calculate the midpoint between two points is equal to

M=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

substitute the values

M=(\frac{1983+1991}{2},\frac{5,047+10,019}{2})

M=(1987,7,533)

therefore

The approximate cost during the year 1987 was $7,533

7 0
3 years ago
PLEASE HELP ITS MY TRIMESTER TEST MY MOM WILL KILL ME IF I FAIL! <3 WILL MARK BRAINLIST!
Masteriza [31]

Answer:

area = area \: of \: two \: semi \: circles + area \: of \: rectangle \\  = 2( \frac{1}{2} \pi {r}^{2} ) + (l \times w) \\  = 2( \frac{1}{2}  \times 3.14 \times  { (\frac{18}{2}) }^{2} ) + (18 \times 4.5) \\  = 254.47 + 81 \\  = 335.5 \:  {ft}^{2}

3 0
3 years ago
Read 2 more answers
Hypothesis Testing for Means with Small Samples
Scorpion4ik [409]

Answer:

Step-by-step explanation:

Hello!

The variable of interest is

X: volume of root beer in a Windsor Bottling Company can.

A sample of n=24 cans was taken and their contents measured, resulting:

X[bar]= 11.4 oz

S= 0.62 oz

Assuming that the variable has a normal distribution X~N(μ;σ²), the parameter of interest is the average contents of the root beer cans of the Windsor Bottling Company (μ)

The claim is that the population mean content of the cans is different from 12 oz, symbolically: μ ≠ 12

The statistical hypothesis (Null and alternative) have to be complementary, exhaustive and mutually exclusive. The null hypothesis is the "no change" hypothesis and always carries the "=" sign.

If the claim is μ ≠ 12, its complement is μ = 12, the expression carrying the "=" sign will be the null hypothesis and its complement will be the alternative hypothesis:

H₀: μ = 12

H₁: μ ≠ 12

α: 0.05

To test the population mean of this normal population, you have to apply a one sample t-test, with statistic:

t= \frac{X[bar]-Mu}{\frac{S}{\sqrt{n} } } ~t_{n-1}

t_{H_0}= \frac{11.4-12}{\frac{0.62}{\sqrt{24} } } = -4.74

This test is two-tailed, using the critical value approach, you have to determine two rejection regions. Meaning, you'll reject the null hypothesis to small values of the statistic or to high values of the statistic.

t_{n-1;\alpha /2}= t_{23;0.025}= -2.069

t_{n-1;1-\alpha /2}= t_{23;0.975}= 2.069

The decision rule is:

If t_{H_0} ≤ -2.069 or if t_{H_0} ≥ 2.069, then you reject the null hypothesis.

If -2.069 < t_{H_0} < 2.069, then you do not reject the null hypothesis.

The value is less than the left critical value, the decision is to reject the null hypothesis.

Then you can say that with a 5% significance level, there is significant evidence to reject the null hypothesis, then the average amount of root beer of the Windsor Bottling Company is different from 12 oz, this means that the claim about the amount of root beer in the cans is correct.

I hope it helps!

6 0
3 years ago
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