Write an equation for the line that passes through the given points (-2,9) And (1 ,-3)

Mathematics

1 answer:

babymother [125]3 years ago

5 0

Answer:

Finding slope: y2-y1/x2-x1

3-9/1+2

=-6/2

Divide 2 from both

=-3/1 or -3

Slope= -3

Finding y-intercept= y=mx+b

Choose any point on the line to plug in the x and the y then plug in the slope.

I choose (1,3)

3=-3×1+b

3=-3+b

Add 3 to both sides

6=b

Y-intercept=6

Equation: y=-3x+6

Step-by-step explanation:

You might be interested in

PLEASE HELP ASAP I WILL GIVE BRAINLIEST AND LOTS OF POINTS <br> (I just need help for the first 7)

ValentinkaMS [17]

Answer:

Step-by-step explanation:

Good luck

4 0

3 years ago

Plz..... Solve this questions for me...

faust18 [17]

$6.\\\text{We know}\ 9=3^2.\ \text{Therefore}\\\\9^2=(3^2)^2\\\\\text{use}\ (a^n)^m=a^{nm}\\\\9^2=(3^2)^2=3^{2\cdot2}=3^4\\\\\boxed{3^4=9^2}\\=================$

$7.\\METHOD\ 1:\\\\\sqrt{7^4}=\sqrt{7^{2\cdot2}}\\\\\text{use}\ (a^n)^m=a^{nm}\\\\=\sqrt{(7^2)^2}\\\\\text{use}\ \sqrt{a^2}=a\ \text{for}\ a\geq0\\\\=\boxed{7^2}\\\\METHOD\ 2:\\\\\text{use}\ a^\frac{m}{n}=\sqrt[n]{a^m}\\\\\sqrt{7^4}=7^\frac{4}{2}=\boxed{7^2}\\=================$

$8.\\5^a\times5^b=5^{11}\\\\a)\\\text{use}\ a^n\times a^m=a^{n+m}\\\\5^a\times5^b=5^{a+b}\\\\5^{a+b}=5^{11}\Rightarrow a+b=11\\\\11\ \text{is odd. The sum of even and odd is odd. Therefore}\ a\ \text{and}\ b\ \text{can't be even.}\\--------------------\\\\b)\\5\ \text{solutions}\\\\11=5+6\\11=4+7\\11=3+8\\11=2+9\\11=1+10$