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3 years ago

Please help!!!! question is/.........

Mathematics

1 answer:

Andrew [12]3 years ago

8 0

Area of circle = 3.14 x 6^2 = 3.14 x 36 = 113.04

1/2 circle = 113.04 / 2 = 56.52

Area of rectangle = 8 x 6 = 48

Area of figure = 48 + 56.52 = 104.52

answer
104.52 ft^2

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Hi I need help on this!!

MA_775_DIABLO [31]

Answer:

VOLUME OF THE CYLINDER=πr²h

=3.14×4²×9

=3.14×16×9

=452.16 mm³

8 0

2 years ago

A rectangular garden must have a perimeter of 150 feet and an area of at least 1200 square feet. Describe the possible lengths o

kipiarov [429]

Answer: 51.86 and 23.14

Step-by-step explanation:

The rectangular garden must have a perimeter of 150 feet

Perimeter of rectangular garden =

2l + 2w=150 -----------1

The rectangular garden must have a perimeter of 150 feet and an area of at least 1200 square feet.

Area of rectangular garden =

l×w= 1200 feet^2 -----------2

From equation 2, l=1200/w

Put l=1200/w in equation 1

2× 1200/w + 2w = 150

(2400/w) +2w = 150

(2400+2w^2)/w =150

2400+2w^2= 150w

2w^2- 150w+2400=0

Using the general formula

w = [-b+-√(b^2-4ac)]/2a

a = 2, b =-150, c=2400

w =[--150+/-√(-150^2-4×2×2400)]/2×2

=[150+/-√(22500-19200)]/4

=[150+/-√3300)]/4

=(150+57.45)/4 or (150-57.45)/4

w= 207.45/4 or 92.55/4

w= 51.86 or w= 23.14

l = 1200/51.86 or l= 1200/23.14

l = 23.14. or l= 51.86

For an area of at least 1200ft^2

The dimensions are 51.86 and 23.14

4 0

3 years ago

Urgent. Factor the trinomial by grouping. Please show work. 14x^2y+9xy^2+y^3. If prime, show how you got prime answer.

ch4aika [34]

Answer:

y x (2x +y) x (7x +y)

Step-by-step explanation:

14x^2y + 9xy^2 +y^3

(Factor the expression)

y x (14x^2 +9xy +y^2)

(Rewrite the expression)

y x (14x^2 + 7xy +2xy +y^2)

(Factor the expression)

y x (7x x(2x +y) + y x (2x +y) )

(Factor the expression)

y x (2x +y) x (7x +y)

:))

3 0

2 years ago

1. Determine the following set of adjustments to the equation then draw the graph !!

suter [353]

Answer:

y = -1 and u = 3.333

Step-by-step explanation:

The given equations are :

3u + y = 9 ...(1)

3u-5y = 15 ...(2)

Subtract equation (2) from (1).

3u + y-( 3u-5y)= 9 -15

y+5y = -6

6y = -6

y = -1

Put the value of y in equation (1).

3u + (-1) = 9

3u-1 = 9

3u = 10

u = 10/3

u = 3.333

The attached figure shows the graph for the above equations.

4 0

3 years ago

HELP!!!!!

podryga [215]

Solve for the x-max or h :\
$-b/(2a)=-8/(2*-2)=2=k$
plug it in to equation to get k:/
$y(2)=-2(2)^2+8(2)+3$
-8+16+3=11=k
$y=a(x-2)^2+11
$
solve for a by pluging (0,0)
then a= -11/4
$y=-11/4(x-2)^2+11$

8 0

3 years ago