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Sonbull [250]
3 years ago
5

Grace rakes leaves everyday for one week. She fills the same number of bags with leaves on each of the 5 weekdays. She fills 11

bags over the weekend. At the end of the week, Grace has filled a total of 26 bags. She wants to know how many bags she filled each weekday.
Mathematics
1 answer:
svlad2 [7]3 years ago
7 0

Answer:

3 bags per weekday

Step-by-step explanation:

Total bags of leaves at the end of the week = 26 bags

Bags of leaves she fills over the weekend = 11 bags

Bags of leaves she fills during weekdays = x bags

Total bags of leaves at the end of the week = Bags of leaves she fills over the weekend + Bags of leaves she fills during weekdays

26 = 11 + x

Subtract 11 from both sides

26 - 11 = 11 - 11 + x

15 = x

x = 15 bags

If she fills the same number of bags with leaves on each of the 5 weekdays.

how many bags she filled each weekday.

Bags she filled each weekday = Total Bags of leaves she fills during weekdays / 5 weekdays

= 15 bags / 5 weekdays

= 3 bags per weekday

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One urn contains one blue ball (labeled B1) and three red balls (labeled R1, R2, and R3). A second urn contains two red balls (R
marusya05 [52]

Answer:

(a) See attachment for tree diagram

(b) 24 possible outcomes

Step-by-step explanation:

Given

Urn\ 1 = \{B_1, R_1, R_2, R_3\}

Urn\ 2 = \{R_4, R_5, B_2, B_3\}

Solving (a): A possibility tree

If urn 1 is selected, the following selection exists:

B_1 \to [R_1, R_2, R_3]; R_1 \to [B_1, R_2, R_3]; R_2 \to [B_1, R_1, R_3]; R_3 \to [B_1, R_1, R_2]

If urn 2 is selected, the following selection exists:

B_2 \to [B_3, R_4, R_5]; B_3 \to [B_2, R_4, R_5]; R_4 \to [B_2, B_3, R_5]; R_5 \to [B_2, B_3, R_4]

<em>See attachment for possibility tree</em>

Solving (b): The total number of outcome

<u>For urn 1</u>

There are 4 balls in urn 1

n = \{B_1,R_1,R_2,R_3\}

Each of the balls has 3 subsets. i.e.

B_1 \to [R_1, R_2, R_3]; R_1 \to [B_1, R_2, R_3]; R_2 \to [B_1, R_1, R_3]; R_3 \to [B_1, R_1, R_2]

So, the selection is:

Urn\ 1 = 4 * 3

Urn\ 1 = 12

<u>For urn 2</u>

There are 4 balls in urn 2

n = \{B_2,B_3,R_4,R_5\}

Each of the balls has 3 subsets. i.e.

B_2 \to [B_3, R_4, R_5]; B_3 \to [B_2, R_4, R_5]; R_4 \to [B_2, B_3, R_5]; R_5 \to [B_2, B_3, R_4]

So, the selection is:

Urn\ 2 = 4 * 3

Urn\ 2 = 12

Total number of outcomes is:

Total = Urn\ 1 + Urn\ 2

Total = 12 + 12

Total = 24

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3 years ago
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2 years ago
Two angles are supplementary if their sun is 180. The larger angle measures five degrees more than four times the measures of a
Jet001 [13]

Answer:

The smaller angle is 35 and the larger one is 145.

Step-by-step explanation:

In order to find this, we need to express the larger angle in terms of the smaller angle (x).

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x = number of people went to movies

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