Answer:
The angle with measure 60° is one of those angles that has a well-known cosine value: cos(60°) its C= 1/2.
Step-by-step explanation:
1/2(12-v)=1/6(v-6)
6-1/2v=1/6v-1
7=2/3v
v=21/2 or 10.5
Answer:
m ∠JPN = 131°
Step-by-step explanation:
m ∠JPL = m ∠MPK Vertical angles are =
7x + 19 = 11x -17 Substitution
- 4x = -36 Algebra: Solving for x
x = 9 Algebra: Solving for x
m ∠JPL = 82° Substitution x = 9 into m ∠JPL = 7x +19
m ∠JPL + m ∠LPK = 180° Definition of linear pair/supplement
angles = 180°
82° + m ∠LPK = 180° Substitution
m ∠LPK = 98° Algebra
m ∠LPK = m ∠LPN + m ∠NPK Angle addition Theorem
PN bisects ∠LPK Given
m ∠LPN = m ∠NPK Definition of angle bisector
98 ° = 2 ( m ∠LPN) Substitution
m ∠LPN = 49° Algebra
m ∠JPN = m ∠JPL + m ∠LPN Angle Addition
m ∠JPN = 82° + 49° Substitution
m ∠JPN = 131° Addition
Answer:
In this problem, I can not tell what is V, so I will answer it in a general way.
A polynomial is something of the form:
a*x^5 + b*x^4 + c*x^3 + d*x^2 + e*x + f
a, b, c, d, e, and f are real numbers and constant.
Where the degree of the polynomial is equal to the greatest power (in this case 5).
You write:
4x^2 + 3Vx + 5
Now, if V is a real number, then we have that this is a polynomial of degree 2.
Because we can write this as:
4*x^2 + (3V)*x + 5
So the answer is true.
Now, if V is a variable or an operation, the answer will be false.
