<span>The maxima of a differential equation can be obtained by
getting the 1st derivate dx/dy and equating it to 0.</span>
<span>Given the equation h = - 2 t^2 + 12 t , taking the 1st derivative
result in:</span>
dh = - 4 t dt + 12 dt
<span>dh / dt = 0 = - 4 t + 12 calculating
for t:</span>
t = -12 / - 4
t = 3
s
Therefore the maximum height obtained is calculated by
plugging in the value of t in the given equation.
h = -2 (3)^2 + 12 (3)
h =
18 m
This problem can also be solved graphically by plotting t
(x-axis) against h (y-axis). Then assigning values to t and calculate for h and
plot it in the graph to see the point in which the peak is obtained. Therefore
the answer to this is:
<span>The ball reaches a maximum height of 18
meters. The maximum of h(t) can be found both graphically or algebraically, and
lies at (3,18). The x-coordinate, 3, is the time in seconds it takes the ball
to reach maximum height, and the y-coordinate, 18, is the max height in meters.</span>
Answer:
11.5 sec
Step-by-step explanation:5.5+6=11.5
Answer:
quarterly N = 4
semi-annually N = 2
Monthly N = 12
annually N = 1
Step-by-step explanation:
Given the following compound interest times :
N = number of times interest is compounded per period :
A period is regarded as a whole year.
Interest compounded;
QUARTERLY = Every 4 months per period = 12/3= 4
SEMI ANNUALLY = Every 6 months per period = 12/6 = 2
MONTHLY = Every month = 12 / 1 = 12
ANNUALLY = Every 12 months = 12 /12 = 1
4/15
Multiple the numerator by numerator, and denominator by denominator, then simplify
The decimal .53 has the 3 in the hundredths place, so the fraction that this was originally is
. When you divide 53 by 100 on your calculator, you will get backk .53
