Answer:
Vertex (-2.5,-300)
Step-by-step explanation:
We are given with h(t)=-16 t^2 +80 t. We are asked to find the vertex.
X-coordinate of vertex =
Where 'a' is coefficient of
term
'b' is coefficient of 't' term.
From given function, a= -16
b=80
So,
x-coordinate of vertex =
=-2.5
y-coordinate of vertex =
Simplify it,
=-100 -200
= -300
So, vertex is at (-2.5, -300).
H= -8. H-2h= 9-1; -h=8; h= -8
When (-5, 2) is reflected across the y-axis then it becomes (5, 2). When (-5, 2) is reflected across the x-axis, it becomes (-5, -2)
I hope this helps out!
Step-by-step explanation:
y=-3+5x
substitute y into equation 2
3x-8y=24
3x-8(-3+5x)=24
3x+24-40x=24
x=0
y=-3+5(0)
y=-3
(x,y)=(0,3)