3x-2 = 5x-14
Subtract 3x from each side:
-2 = 2x -14
Add 14 to each side:
12 = 2x
Divide both sides by 2:
x = 12/2
x = 6
The answer is B. x > -22
-5x + 20 < 130
-5x < 130 - 20
-5x < 110
-5x/-5 > 110/-5
x > -22
<span>Let r(x,y) = (x, y, 9 - x^2 - y^2)
So, dr/dx x dr/dy = (2x, 2y, 1)
So, integral(S) F * dS
= integral(x in [0,1], y in [0,1]) (xy, y(9 - x^2 - y^2), x(9 - x^2 - y^2)) * (2x, 2y, 1) dy dx
= integral(x in [0,1], y in [0,1]) (2x^2y + 18y^2 - 2x^2y^2 - 2y^4 + 9x - x^3 - xy^2) dy dx
= integral(x in [0,1]) (x^2 + 6 - 2x^2/3 - 2/5 + 9x - x^3 - x/3) dx
= integral(x in [0,1]) (28/5 + x^2/3 + 26x/3 - x^3) dx
= 28/5 + 40/9 - 1/4
= 1763/180 </span>
This is how you do it! Please let me know if you need help.