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3 years ago

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1 answer:

azamat3 years ago

3 0

Answer:

$\frac{3}{x}+\frac{x}{x+2}= \frac{x^2+3x+6 }{x^2+2x}$

Step-by-step explanation:

Given

$\frac{3}{x}+\frac{x}{x+2}$

Required

Solve

$\frac{3}{x}+\frac{x}{x+2}$

Take LCM

$\frac{3(x+2) + x * x}{x(x+2)}$

$\frac{3(x+2) + x^2}{x(x+2)}$

Open brackets

$\frac{3x+6 + x^2}{x^2+2x}$

Rewrite as:

$\frac{x^2+3x+6 }{x^2+2x}$

Hence:

$\frac{3}{x}+\frac{x}{x+2}= \frac{x^2+3x+6 }{x^2+2x}$

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Aleks [24]

$3 \sqrt{7} \times 17 \sqrt{14}$

This is the problem that we need to solve. The best way to get about it is to first:

Multiply the constant numbers (3 and 17). 3×17 is 51.
Next multiply the radicals.
$\sqrt{7} \times \sqrt{14} = \sqrt{7 \times 14} = \sqrt{108}$
Simplify the squareroot of 108 since it is 49 times 2. It would be equal to 7 squareroots of 2.
Our final answer would be:
$51 \times 7\sqrt{2} = 357 \sqrt{2}$
51 x 7 is 357, so the answer above is right.