Question

}{x+2}" alt="\frac{3}{x}+\frac{x}{x+2}" align="absmiddle" class="latex-formula">

Answer 1

Answer:

$\frac{3}{x}+\frac{x}{x+2}= \frac{x^2+3x+6 }{x^2+2x}$

Step-by-step explanation:

Given

$\frac{3}{x}+\frac{x}{x+2}$

Required

Solve

$\frac{3}{x}+\frac{x}{x+2}$

Take LCM

$\frac{3(x+2) + x * x}{x(x+2)}$

$\frac{3(x+2) + x^2}{x(x+2)}$

Open brackets

$\frac{3x+6 + x^2}{x^2+2x}$

Rewrite as:

$\frac{x^2+3x+6 }{x^2+2x}$

Hence:

$\frac{3}{x}+\frac{x}{x+2}= \frac{x^2+3x+6 }{x^2+2x}$