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Masteriza [31]
3 years ago
11

Given the cosine equation y = 2cos(4x) - 1, What is the midline?

Mathematics
1 answer:
pogonyaev3 years ago
6 0

Answer:

y = 2 \cos(4x)  - 1 \\ when \: y = 0 \\  \cos(4x)  =  \frac{1}{2}  \\ 4x = 60 \\ x = 15 \\ when \: x = 0 \\ y = 2 - 1 = 1 \\ intercepts =  > (15, \: 0) \: and \: (0, \: 1) \\ midpoints : ( \frac{15 + 0}{2} , \:  \frac{0 + 1}{2} ) \\  = (7.5, \: 0.5) \\ gradient =  \frac{1 - 0}{0 - 15}  \\  =  -  \frac{1}{15}  \\ y = mx + c \\ at \: (7.5, \: 0.5) \\ 0.5 =  -  \frac{1}{15}  \times 7.5 + c \\ 0.5 =  - 0.5 + c \\ c = 1 \\  \therefore \: y =  -  \frac{1}{15} x + 1 \\  =  > 15y =  - x + 15

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