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Hunter-Best [27]
3 years ago
15

Plsss help me if you know????

Mathematics
2 answers:
Margaret [11]3 years ago
8 0

Answer:

n = 3

Step-by-step explanation:

There's two ways, first cross multiplication:

n/6 = 1/2

Cross multiplication so 2 times n and 6 times 1

2n = 6

n = 3

Second way:

n/6 = 1/2

(n/6 = 1/2) times 6

n = 6/2

n = 3

marishachu [46]3 years ago
6 0

Answer:

n/6 = 1/2

2n = 6

n = 3

Hope my answer is correct

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A stunt car drives off a 150m cliff at a speed of 45mph
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5.53 seconds.

Step-by-step explanation:

The equation of motion is

d = 4.9t^2 so

150 = .9 t^2

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4 years ago
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About 13​% of the population of a large country is nervous around strangersnervous around strangers. If two people are randomly​
Molodets [167]

Answer:

1.69% probability both are nervous around strangers.

24.31% probability at least one is nervous around strangers.

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they are nervous around strangers, or they are not. The people are chosen randomly, which means that the probability of a person being nervous around strangers is independent from other people. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

About 13​% of the population of a large country is nervous around strangers.

This means that p = 0.13.

Two people are randomly​ selected

This means that n = 2.

What is the probability both are nervous around strangers?

This is P(X = 2)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{2,2}.(0.13)^{2}.(0.87)^{0} = 0.0169

1.69% probability both are nervous around strangers.

What is the probability at least one is nervous around strangersnervous around strangers?

This is P(X \geq 1)

P(X \geq 1) = P(X = 1) + P(X = 2)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{2,1}.(0.13)^{1}.(0.87)^{1} = 0.2262

P(X = 2) = C_{2,2}.(0.13)^{2}.(0.87)^{0} = 0.0169

P(X \geq 1) = P(X = 1) + P(X = 2) = 0.2262 + 0.0169 = 0.2431

24.31% probability at least one is nervous around strangers.

3 0
3 years ago
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