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FrozenT [24]
3 years ago
15

School games & Others Solve.

Mathematics
1 answer:
insens350 [35]3 years ago
5 0

Answer:

3.24!

Step-by-step explanation:

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E Word mellem with addition et subtraction of 2 decimals Abdulu put 1253 gallons of fuel to cart There were 6.9 gallions in the
ololo11 [35]

Answer:

We saw in the last video that when you multiply or you divide numbers, or (I guess I should say when you multiply or divide measurements) your result can only have as many significant digits as the thing with the smallest significant digits you ended up multiplying and dividing. So just as a quick example, if I have 2.00 times (I don't know) 3.5 my answer over here can only have 2 significant digits This has 2 significant digits, this has 3. 2 times 3.5 is 7, and we can get

4 0
2 years ago
Solve for x (5x-3)/4 = x/3 + 1 and please show working out
Mila [183]
(5x-3)/4 = x/3 +1  
5x-3 = 4x/3 +4 
5x - 4x/3 = 7
(11/3)x = 7 
x = 7/(11/3) = 21/11

4 0
4 years ago
A line with a slope of 1 passes through the point (0, 2)What is its equation in slope-intercept form?
devlian [24]

Answer:

y=x+2

Step-by-step explanation:

y-y1=m(x-x1)

y-2=1(x-0)

y-2=1(x)

y-2=x

y=x+2

5 0
3 years ago
I have some cheese. I used
hram777 [196]
<h3>Answer:     2500 grams</h3>

============================================

Work Shown:

A = amount of grams of cheese you had originally

B = (2/5)*A = amount of cheese you use up after day 1

C = (3/5)*A = amount of cheese you have left over after day 1

note how B and C add back up to 'A'.

This is because 2/5+3/5 = 5/5 = 1, so,

B+C = (2/5)A+(3/5)A = (2/5+3/5)A = 1*A = A

--------------

D = (2/5)*C = amount of cheese you use up after day 2

E = (3/5)*C = amount of cheese left over after day 2

the variables D and E add up to C

we are told that there are 900 grams of cheese left after day 2, so E = 900

--------------

E = (3/5)*C

(3/5)*C = E

(3/5)*C = 900 ... Plug in E = 900

3C = 900*5 .... multiply both sides by 5

3C = 4500

C = 4500/3 .... divide both sides by 3

C = 1500

This means you had 1500 grams of cheese after day 1

-------------

C = (3/5)*A

(3/5)*A = C

(3/5)*A = 1500 ... plug in C = 1500

3A = 1500*5 ... multiply both sides by 5

3A = 7500

A = 7500/3 .... divide both sides by 3

A = 2500

-----------

<h3>You started off with 2500 grams of cheese.</h3>

After day 1, you use up (2/5)*2500 = 1000 grams of cheese and have 2500-1000 = 1500 grams left over.

After day 2, you use up (2/5)*1500 = 600 grams of cheese and have 1500-600 = 900 grams left over.

The answer is confirmed.

6 0
4 years ago
he mean age of bus drivers in Chicago is greater than 54.4 years. If a hypothesis test is performed, how should you interpret a
Natalka [10]

Answer:

There is not sufficient evidence to support the claim μ > 54.4.

Step-by-step explanation:

1) Previous concepts

A hypothesis is defined as "a speculation or theory based on insufficient evidence that lends itself to further testing and experimentation. With further testing, a hypothesis can usually be proven true or false".  

The null hypothesis is defined as "a hypothesis that says there is no statistical significance between the two variables in the hypothesis. It is the hypothesis that the researcher is trying to disprove".

The alternative hypothesis is "just the inverse, or opposite, of the null hypothesis. It is the hypothesis that researcher is trying to prove".

2) Solution to the problem

On this case we want to test is \mu>54.4 and the system of hypothesi on this case are:

Null Hypothesis: \mu \leq 54.4

Alternative hypothesis:\mu >54.4

On this case is our decision is FAILS to reject the null hypothesis then we can conclude that we don't have enough evidence to support the claim at the significance level provided.  So the correct conclusion would be:

There is not sufficient evidence to support the claim μ > 54.4.

8 0
3 years ago
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