Question

Three Nissans, two Fords, and four Chevrolets can be rented for $106 per day. At the same rates two Nissans, four Fords, and three Chevrolets cost $107 per day, whereas four Nissans, three Fords, and two Chevrolets cost $102 per day. Find the rental rate for the Fords.

Answer 1

Answer:

The rental rate for the Fords is of $12 per day.

Step-by-step explanation:

This question is solved using a system of equations.

I am going to say that:

x is the cost of a Nissan.

y is the cost of a Ford.

z is the cost of a Chevrolet.

Three Nissans, two Fords, and four Chevrolets can be rented for $106 per day.

This means that:

$3x + 2y + 4z = 106$

Two Nissans, four Fords, and three Chevrolets cost $107 per day

This means that:

$2x + 4y + 3z = 107$

Four Nissans, three Fords, and two Chevrolets cost $102 per day.

This means that:

$4x + 3y + 2z = 102$

From the first equation:

$4z = 106 - 3x - 2y$

$2z = 53 - 1.5x - y$

$z = 26.5 - 0.75x - 0.5y$

Replacing into the third equation:

$4x + 3y + 53 - 1.5x - y = 102$

$2.5x + 2y = 49$

From the second equation:

$2x + 4y + 3z = 107$

$2x = 107 - 4y - 3z$

$x = 53.5 - 2y - 1.5z$

$x = 53.5 - 2y - 1.5(26.5 - 0.75x - 0.5y)$

$x - 1.125x = 53.5 - 2y - 39.75 + 0.75y$

$-0.125x = 13.75 - 1.25y$

$0.125x = 1.25y - 13.75$

$x = \frac{1.25y - 13.75}{0.125}$

$x = 10y - 110$

Find the rental rate for the Fords.

We have to find y, so:

$2.5x + 2y = 49$

$2.5(10y - 110) + 2y = 49$

$25y - 275 + 2y = 49$

$27y = 324$

$y = \frac{324}{27}$

$y = 12$

The rental rate for the Fords is of $12 per day.