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rjkz [21]
3 years ago
6

Factor 7w2−175.(1 point) −7(w−25) 7(w−25) 7(w−5)(w+5) 7(w−5)(w−5)

Mathematics
1 answer:
Nutka1998 [239]3 years ago
6 0

Answer:

7(w + 5)(w -5)

Step-by-step explanation:

a² - b² = (a + b)(a - b)

7w² - 175 = 7w² - 7*25

              = 7(w² - 25)

              = 7(w² - 5²)

              = 7(w + 5)(w -5)

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1. Find the vertex of the following: y = (x - 4)(x - 10) *
horsena [70]

Answer:

1. (7,-9)

2. (4,0) and (10,0)

3. (3,0) and (-3,0)

4. (0,-9)

5. (-1,-32)

Step-by-step explanation:

To find the vertex use the formula

\frac{-b}{2a}

First make the equation into a quadratic equation.

(x-4)(x-10)\\x^{2} -10x-4x+40\\x^{2} -14x+40

Now it is in the form

ax^{2} +bx+c=0

Now we can substitute the values

\frac{-(-14)}{2(1)} \\\frac{14}{2} \\7

Now we have 7 as our x value for the vertex we can substitute for y,

x^{2} -14x+40=y\\(7)^{2} -14(7)+40=y\\49-98+4=y\\y=-9

So the vertex for 1 is (7,-9)

To find the intercepts for 2 & 3, they basically already give it to you. You just need to find a value for x for x-4 that will equal it to 0 and another for x for x-10 that will equal it to 0.

x-4=0\\x=4\\\\x-10=0\\x=10

4 is slightly different but start the same,

(x-3)(x+3)\\x^{2}+3x-3x-9\\x^{2}-9

Here, c (9) just shows the graph move down 9, so the y intercept = 9.

5 is the same process as 1,

2(x-3)(x+5)\\2(x^{2}+5x-3x-15)\\2(x^{2}+2x-15)\\2x^{2}+4x-30

Vertex,

\frac{-(4)}{2(2)} \\\frac{-4}{4} \\-1

Substitute,

2x^{2}+4x-30\\2(-1)^{2}+4(-1)-30\\2-4-30\\-32

So the vertex is (-1,-32)

8 0
3 years ago
Answer m/40 + 50 = 51
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Answer:

m=40

Step-by-step explanation:

First you would subtract 50 from both sides to get -> m/40=1. So finally if you want to multiply 40 to both sides it would be m=40. Hope this helps!

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2 years ago
Solve the equation. Then check your solution
kondaur [170]

Answer:

  • Option <u>B </u>is correct i.e. <u>2</u><u>1</u>

Step-by-step explanation:

In the question we're provided with an equation that is :

  • v/7 = 3

And we are asked to find the solution for the equation .

<u>Solution</u><u> </u><u>:</u><u> </u><u>-</u>

<u>\longrightarrow \:  \frac{v}{7}  = 3</u>

Multiplying by 7 on both sides :

\longrightarrow \: \frac{v}{ \cancel{7} }\times  \cancel{7}  = 3 \times 7

On further calculations , we get :

\longrightarrow \:  \blue{\boxed{v = 21}}

  • <u>Therefore</u><u> </u><u>,</u><u> </u><u>solution</u><u> </u><u>for</u><u> equation</u><u> </u><u>is </u><u>2</u><u>1</u><u> </u><u>.</u><u>That </u><u>means</u><u> </u><u>option </u><u>B </u><u>is </u><u>the </u><u>correct</u><u> answer</u><u>.</u>

<u>Verifying</u><u> </u><u>:</u>

We are verifying our answer by substituting value of v in the equation given in question :

\longrightarrow \: \frac{v}{7}  = 3

Putting value of v :

\longrightarrow \:  \cancel{\frac{21}{7}}  = 3

By dividing 21 with 7 , we get :

\longrightarrow \:3 = 3

\longrightarrow \: L.H.S=R.H.S

\longrightarrow \: Hence , \: Verified.

  • <u>Therefore</u><u> </u><u>,</u><u> </u><u>our </u><u>answer</u><u> is</u><u> valid</u><u> </u><u>.</u>

<h2><u>#</u><u>K</u><u>e</u><u>e</u><u>p</u><u> </u><u>Learning</u></h2>
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2 years ago
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