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Vsevolod [243]
3 years ago
8

To prove ∆LMN ≅ ∆PQR by SSS you need _______________ and ______________ and ______________

Mathematics
1 answer:
Elis [28]3 years ago
6 0

Given:

To prove ∆LMN ≅ ∆PQR by SSS you need _____________ and

_______________ and ______________.

To find:

The missing values.

Solution:

If ∆LMN ≅ ∆PQR by SSS, then all sides of ∆LMN are congruent to corresponding sides of ∆PQR.

LM\cong PQ

MN\cong QR

LN\cong PR

Therefore, the missing values are LM\cong PQ, MN\cong QR,LN\cong PR.

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A right triangle has a hypotenuse of 10 feet and a leg of 6 feet. What is the length of the other leg?
Artemon [7]

Answer:

The other length of the leg is <em>8 feet.</em>

Step-by-step explanation:

To find the answer we have to find what<em> 10</em> and <em>6 is squared.</em>  <em>10 x 10 = 100</em>.  

<em>6 x 6 = 36.  </em>Now since we are trying to find the length of the other leg, we will <em>subtract 100 from 36</em> and we get <em>64</em>.  Then for the last step, we will figure out what number<em> squared equals 64.</em>  Because 8 x 8 = 64, <em>8 is our answer.</em>

3 0
2 years ago
Simplify: cos2x-cos4 all over sin2x + sin 4x
GrogVix [38]

Answer:

\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}=\tan\left(x\right)

Step-by-step explanation:

\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}

Apply formula:

\cos\left(A\right)-\cos\left(B\right)=-2\cdot\sin\left(\frac{A+B}{2}\right)\cdot\sin\left(\frac{A-B}{2}\right) and

\sin\left(A\right)+\sin\left(B\right)=2\cdot\sin\left(\frac{A+B}{2}\right)\cdot\sin\left(\frac{A-B}{2}\right)

We get:

=\frac{-2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\sin\left(\frac{2x-4x}{2}\right)}{2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\cos\left(\frac{2x-4x}{2}\right)}

=\frac{-\sin\left(\frac{2x-4x}{2}\right)}{\cos\left(\frac{2x-4x}{2}\right)}

=\frac{-\sin\left(\frac{-2x}{2}\right)}{\cos\left(\frac{-2x}{2}\right)}

=\frac{-\sin\left(-x\right)}{\cos\left(-x\right)}

=\frac{-\cdot-\sin\left(x\right)}{\cos\left(x\right)}

=\frac{\sin\left(x\right)}{\cos\left(x\right)}

=\tan\left(x\right)

Hence final answer is

\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}=\tan\left(x\right)

6 0
2 years ago
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Step-by-step explanation:

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