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Arisa [49]
3 years ago
7

The area of a circle is 100π cm2, find the radius of the circle.

Mathematics
1 answer:
MAVERICK [17]3 years ago
3 0

<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em>⤴</em>

<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em>

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Marquis is hungry for pizza! He has a choice between pizza A: Half of a 16 inch pizza or pizza B: A whole 10 inch pizza to himse
aliina [53]

Answer:

The 10 inch one because half of 16 is 8 so he would only get 8 inches of pizza.

Step-by-step explanation:

5 0
3 years ago
Suppose that is in standard position and the given point is on the terminal side of 0. Give the exact value of the indicated tri
Lilit [14]

Answer:

  12/13

Step-by-step explanation:

The length of the segment from the origin to the terminal point is ...

  r = √((-5)² +12²) = √169 = 13

The sine of the angle is the ratio of the y-coordinate to this distance

  sin(θ) = y/r = 12/13

_____

Additional comment

The other trig functions are ...

  cos(θ) = x/r = -5/13

  tan(θ) = y/x = -12/5

This is a 2nd-quadrant angle, where the sine is positive, but the cosine and tangent are negative.

6 0
2 years ago
How long will it take for an investment to triple, if interest is compounded continuously at 4%?
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3 0
3 years ago
The triangles are similar.<br> What is the value of x?<br> Enter your answer in the box.<br> X=
Volgvan
X=21

If the triangle are similar then you can divide.
75 divided by 25 is 3
72 divided by 21 is 3
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3 0
3 years ago
Read 2 more answers
Given JM=27, ml=16, jl=46, nk=15, KLM= 48, JkM=78, MJL=22, find each missing value.
Llana [10]

Answer:

KL = 27

JK = 16

MK = 30

NL = 23

m∠JKL = 132°

m∠KLJ = 22°

m∠KMJ = 54°

m∠KJL = 26°

Step-by-step explanation:

The given parameters of the quadrilateral JKLM are;

JM = 27, ML = 16, JL = 46, NK = 15, KLM = 48, JKM = 78, MJL = 22

Taking the sides as parallel, we have that quadrilateral JKLM is a parallelogram

Therefore;

KL = JM = 27

JK = ML = 16

m∠KLJ = m∠MJL = 22°

MN = NK = 15

MK = MN + NK = 15 + 15 = 30

NL = JL/2 = 46/2 = 23

m∠KJM = m∠KLM = 48°

m∠KJL = m∠KLM - m∠MJL = 48° - 22° = 26°

m∠KML = m∠JKM = 78°

m∠MKL = 180° - m∠KML - m∠KLM = 180° - 78° - 48° = 54°

m∠MKL = 54°

m∠JKL = m∠JKM + m∠MKL = 78° + 54° = 132°

m∠KMJ = m∠MKL = 54°

3 0
3 years ago
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